Let a set of

elements.
We can find

(factorial) of the

element.
However, combination of the element lead to less than

possibilities.
(combining like adding or multiplying)
So the proposition is false.
Answer:
702 emails
Step-by-step explanation:
<h2>This problem bothers on depreciation of value, in this context it is Joe's email that has depreciated by 10%.</h2>
Given data
Average personal emails received monthly = 
Average work emails received monthly
We are required to solve for the new amount of emails Joe will be receiving after changing his address, to find this value we need to solve for the depreciation of his personal mails.
After solving for the depreciation , we then need to subtract the depreciation from the initial number of mails to get the new number of mails.
let us solve for 10% depreciation.

The new number of mails

Joe will be receiving an average of 702 emails in his personal account monthly
Answer:
18
Step-by-step explanation:
There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.
The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.
<span>Using the formula above, your merit increase will be 2.5%. You received a score of 3.4 on your annual review. Since the merit increase model is 0.5% salary increase at a score of 2.6, with an additional 1% for every .4 points above that baseline, you get 2.5%, which is the baseline of 0.5% + 2% for the 0.8 points you scored above that baseline.</span>
Answer:
A and C
Step-by-step explanation:
To determine which events are equal, we explicitly define the elements in each set builder.
For event A
A={1.3}
for event B
B={x|x is a number on a die}
The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as
B={1,2,3,4,5,6}
for event C
![C=[x|x^{2}-4x+3]\\solving x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1](https://tex.z-dn.net/?f=C%3D%5Bx%7Cx%5E%7B2%7D-4x%2B3%5D%5C%5Csolving%20%20x%5E%7B2%7D-4x%2B3%5C%5Cx%5E%7B2%7D-4x%2B3%3D0%5C%5Cx%5E%7B2%7D-3x-x%2B3%3D0%5C%5Cx%28x-3%29-1%28x-3%29%3D0%5C%5Cx%3D3%20or%20x%3D1)
Hence the set c is C={1,3}
and for the set D {x| x is the number of heads when six coins re tossed }
In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6
Hence the set D can be expressed as
D={0,1,2,3,4,5,6}
In conclusion, when all the set are compared only set A and set C are equal