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kipiarov [429]
2 years ago
14

Bethany sells roses and petunias. The expression 3r+2.5p3r+2.5p3, r, plus, 2, point, 5, p gives the cost (in dollars) of rrr ros

es and ppp petunias.
What is the cost of 777 roses and 888 petunias?
Mathematics
1 answer:
Vaselesa [24]2 years ago
3 0

Answer:

I think the equation is written as 3r + 2.5p, where r is the number of roses and p is the number of petunias. To find the total cost, substitute 777 to r and 888 to p. The total cost would then be:

Total Cost = 3r + 2.5p

Total Cost = 3(777) + 2.5(888)

Total Cost = 4551

The total cost would be $4,551.

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comparing permutations to combinations for the same set of parameters you would have more combinations than permutations true or
ella [17]
Let a set of n elements. 
We can find n! (factorial) of the n element. 
However, combination of the element lead to less than n! possibilities. 
(combining like adding or multiplying)
So the proposition is false. 
6 0
2 years ago
Read 2 more answers
Joe receives an average of 780 emails in his personal account and 760 emails in his work account each month. After changing his
Semmy [17]

Answer:

702 emails

Step-by-step explanation:

<h2>This problem bothers on depreciation of value, in this context it is Joe's email that has depreciated by 10%.</h2>

Given data

Average personal emails received monthly = 780 emails

Average work emails received monthly= 760 emails

     

      We are required to solve for the new amount of emails Joe will be receiving after changing his address, to find this value we need to solve for the depreciation of his personal mails.

      After solving for the depreciation , we then need to subtract the depreciation from the initial number of mails to get the new number of mails.

let us solve for 10% depreciation.

depreciation= \frac{10}{100} *780\\depreciation=0.1*780= 78 emails

The new number of mails

= initial number of mail- depreciation\\ =780-78= 702 emails

Joe will be receiving an average of 702 emails in his personal account monthly

7 0
2 years ago
A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0
2 years ago
Congratulations you received a score of 3.4 on your annual review . Merit increases are given out starting at .5% at a score of
defon
<span>Using the formula above, your merit increase will be 2.5%. You received a score of 3.4 on your annual review. Since the merit increase model is 0.5% salary increase at a score of 2.6, with an additional 1% for every .4 points above that baseline, you get 2.5%, which is the baseline of 0.5% + 2% for the 0.8 points you scored above that baseline.</span>
6 0
1 year ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
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