Answer:
<em>c = -30 N</em>
<em />
Explanation:
Initial length L1 = 30 cm
Initial restoring force F1 = -35 N
Final length L1 = 90 cm
Final restoring force F2 = -125 N
Between 30 cm and 90 cm, one will increase extension by 20 cm 3 times. This means the force between -35 N to -125 N increased by 3 constant value.
-125 - (-35) = -90 N.
this means that the constant is,
<em> c = -90/3 = -30 N</em>
<em>This means that for every 20 cm increase, there is a 30 N decrease in the restoring force</em>
The answer is ...
150 this is how you find it
Ok so you 10,000 cars you divide that by 200
That is going to give you 50 groups of 200 and if each 200 cars have 3 cars with a defect you just do 50•3
Which is how you get 150 cats
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Hope this helps:)
