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Vesnalui [34]
2 years ago
11

Chill, a beverage manufacturer, offers varied versions of its products that include diet, cherry, vanilla and caffeine-free vers

ions in addition to its original product. With respect to market coverage alternatives, the given scenario reflects the company's decision to cater to ___________
Business
1 answer:
STatiana [176]2 years ago
7 0

Answer:

<em>A differentiated market</em>

Explanation:

<em>Whenever a business produces initiatives that cater to at least two product categories or targeted groups, a differentiated marketing strategy is applied</em>.

For instance, a retailer may encourage a purchase in at least two towns or locations that caters to people, or even a business can market a brand which appeals to women in at least two age categories.

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The process of continuously updating, improving, and detailing a project management plan, or parts of a project management plan,
Zina [86]

Answer:

progressive elaboration

Explanation:

progressive elaboration is an important part or step of project management plan, it is the process of continously updating, improving and detailing a project management plan, or part of it as new specific information becomes available. it is use to improve the project management plan

3 0
2 years ago
The Sports Club plans to pay an annual dividend of $1.20 per share next year, $1.12 per share a year for the following two years
Delicious77 [7]

Answer:

$9.63

Explanation:

Data provided in the question:

Year              Annual dividend paid

   1                                      $1.20

   2                                      $1.12

   3                                      $1.12

   4                                      $14.20

Now,

Year       Annual dividend paid        Present value factor     Present value

   1                              $1.20                          0.84246               1.011

   2                             $1.12                          0.84246               0.7949

   3                             $1.12                          0.59793             0.6696

   4                             $14.20                       0.50373             7.1529

===============================================================

Worth of stock = 1.011 + 0.7949 + 0.6696 + 7.1529

= $9.6284 ≈ $9.63

Note:

Present value factor = [ 1 ÷ (1 + 0.187)ⁿ]

here,

n is the year

7 0
2 years ago
On January 1, 20Y8, Crabb &amp; Co. sold land to ASP, Inc. and accepted a two-year, $500,000 face value note as payment. 6% inte
jeka94

Answer:

1. Discount

2. $449,298.47

3. $369,298.47 gain

4. land reduces by $80,000, investment increases by $449,298.47, reserves increases by $369,298.47

Explanation:

Question 1

Using the formula below

Price=\frac{I_{1}}{1+r} +\frac{I_{2}+F}{(1+r)^{2}}

where

I = interest rate, which is 6% of 500,000 = 30,000

F = Face value, 500,000

r = borrowing cost = 12%

Therefore, the price of the note at the time it was used for payment was

Price=\frac{30,000}{1.12} +\frac{30,000+500,000}{(1.12)^{2}}

= $449,298.47.

As the price is lower than the face value of the note, the note was issued at a discount.

Question 2

The fair market value of the note is $449,298.47, the compute price in question 1.

Question 3

The gain/loss on the sale of the land

= sale price - purchase price

= $449,298.47 - 80,000

= $369,298.47.

Question 4

The transaction would affect Crabb & Co's balance sheet as follows.

<em>Asset side:</em>

land reduces by $80,000

investment increases by $449,298.47

<em>Equity & liabilities side:</em>

reserves increases by $369,298.47

3 0
2 years ago
Assume that a certain product has the demand function given by
ss7ja [257]
What is the question? sorry I can't help
3 0
2 years ago
A certain project has three activities on its critical path. Activity A’s normal completion time is five days. It can be crashed
Snowcat [4.5K]

Answer:

Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.

Explanation:

activity A =

normal time (NT) = 5 days

Normal cost (NC) = $0

crash time (CT) = 3 days

Crash cost (CC) = $500

crash cost per day = [CC - NC]/[CT - NT] = $250/day

activity B:

normal time (NT) = 6 days

Normal cost (NC) = $0

crash time (CT) = 4 days

Crash cost (CC) = $50

crash cost per day = [CC - NC]/[CT - NT] = $25/day

activity C:

normal time (NT) = 8 days

Normal cost (NC) = $0

crash time (CT) = 3 days

Crash cost (CC) = $1000

crash cost per day = [CC - NC]/[ CT- NT] = $200/day

The activity that takes the least cost to speed up is the first one to be crashed. from the computations, activity B takes the least cost to speed up, so the project manager should crash activity B first by 2 days.

Therefore, Acitivy B should be crashed first by 2 days and Activity B has a crash cost per days of $25, it will be crashed for a total of $50.

6 0
2 years ago
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