Answer:
The sample a which is solid at 20°C is "Iodine"
The sample b which is liquid at 20°C is "Bromine"
The sample c which is gas at 20°C is "Chlorine"
Explanation:
Iodine : It starts melting at 113.7°C, so the solid sample found is the iodine. Iodine is present in both solid as well as in vapor state. Basically it is kept in closed jars. Only when it reaches the temperature above the melting point is starts melting.
Bromine: It is a non metallic element that is present in the liquid state, being a member of halogen group. It is heavy, mobile and dangerous reddish brown liquid. It is corrosive in nature, when comes in contact with human tissue and causes irritation in eye when comes in contact with its vapor.
Chlorine: In room temperature it is gas, as it has weak intermolecular interaction which fails to keep the molecules closely attached.
1. The phrase Darwin used to describe his broad theory of evolution is ''descent with modification.
2. All of life is related through common ancestry, accounting for the Unity.
Answer:
True
Explanation:
When the resting potential of the membrane is changed, the membrane becomes either more negative inside or less negative. This small deviation from the resting potential is called graded potential. A graded potential occurs when a stimulus triggers opening or closing of the mechanically gated or ligand-gated channels present in the plasma membrane.
For example, the presynaptic neuron releases neurotransmitters in response to a nerve impulse. The neurotransmitter binds to receptors present in the plasma membrane of the postsynaptic neuron and triggers the opening of the ion channels to allow the inflow of particular ions to flow. The flow of ions changes the voltage across the membrane. This change in membrane voltage is a postsynaptic potential and is a type of graded potential.
<span> Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles.
Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype.
Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons.
Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples.
Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous.
PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper.
Pheww... done.. Hope this helps! :)<span>
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Answer:
The correct answer is B. weight loss
Explanation:
Calorie is considered a unit of energy and athletes like basketball players require more calories than common people. Calories are present in our food and every food provide a different amount of calories to us.
To gain weight people require to consume more calories than they burn and to reduce weight people must burn more calories than they consume. So losing weight by theo shows that theo is not taking enough calories to support his activity.
Therefore theo should improve the calorie intake up to that level where he can maintain his body weight. Therefore the correct answer is B.
