the answer to this question is the last one i think it might be the first one
If the extreme phenotypes are crossed while the progeny have intermediate phenotypes, then it would be an incomplete dominance. Which would be B.
<span>Let the equation be : at^2 + bt + c = P,
where t = time (hrs),
P = population (1000's).
When t = 1, P = 3.03.
When t = 2, P = 1.72.
When t = 3, P = 1.17.
Substitute these into the equation to obtain these 3 simultaneous equations :
a + b + c = 3.03
4a + 2b + c = 1.72
9a + 3b = c = 1.17
Solving gives :
a = 0.38,
b = -2.45,
c = 5.1.
The equation is therefore,
P = 0.38t^2 - 2.45t + 5.1
Testing with t = 0 to 6 gives the population values as provided,
so it seems to be a valid model.
At t = 9 hrs,
P = 0.38*9^2 - 2.45*9 + 5.1
= 13.83.</span>
