Question

Which graph shows the solution to the system of linear inequalities? y < 2x – 5 y > –3x + 1 On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the right of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the right of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first solid line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second dashed line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded. On a coordinate plane, 2 straight lines are shown. The first dashed line has a negative slope and goes through (0, 1) and (1, negative 2). Everything to the left of the line is shaded. The second solid line has a positive slope and goes through (0, negative 5) and (2, negative 1). Everything to the left of the line is shaded.

Answer 1

Answer:

y<2x+2 and -1,-2

Step-by-step explanation:

did it edge2020

Answer 2

Answer:

to graph the inequality

y<2x-5

We graph the dashed boundary line y=2x-5 with a positive slope of 2 and y-intercept (0,-5) and shade everything to the right.

To graph the inequality y>-3x+1, we graph the dashed boundary line y=-3x +1 with y-intercept (0,1) and shade every above it.

The intersection of the two shadings is the solution to the system of inequalities:

y<2x-5

and

y<-3x+1

ANSWER IS B

Step-by-step explanation: