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AysviL [449]
2 years ago
8

A pizza lover wants to compare the average delivery times for four local pizza restaurants. Over the course of a few weeks, he o

rders a number of pizzas from each restaurant, and he records the time it takes for each pizza to be delivered.
a) When performing an ANOVA with this data, what is the alternative hypothesis?O All of the restaurants have different mean delivery timesO At least two of the restaurants have different mean delivery timesO Two of the restaurants have different mean delivery timesO One of the restaurants has a different mean delivery time than the others
Mathematics
1 answer:
xenn [34]2 years ago
8 0

Answer:

At least two of the restaurant have different mean delivery time.

Step-by-step explanation:

The ANOVA known as Analysis of variance involves the hypothesis testing of means on the basis of variances. The null hypothesis in ANOVA is taken as the equality mean i.e. H0: All means are equal. Whereas alternative hypothesis consists of at least two means are not equal.

The problem states that a pizza lover is comparing average delivery time. The null and alternative hypothesis in this case would be

H0: All restaurant have equal mean delivery time.

H1: At least two restaurant have different mean delivery time.

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Answer:

I) 32.5

ii) 100.1

Step-by-step explanation:

I) 1056.25 = √1056.25

= 32.5

ii) 10020.01= √10020.01

=100.1

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A store makes a profit of $18 on a blanket after a markup of 30%. What is the selling price of the blanket?
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Orlando bought a new couch for $2,904, using the furniture store's finance plan. He will pay $121 a month for 24 months. Which e
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2 years ago
If a hurricane was headed your way, would you evacuate? The headline of a press release states, "Thirty-four Percent of People o
IgorC [24]

Answer:

The 98% confidence interval would be given by (0.326;0.354)

Step-by-step explanation:

1) Notation and definitions

X=63 number of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

n=6138 random sample taken

\hat p=0.34 estimated proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

p true population proportion of people who live within 20 miles of the coast in high hurricane risk counties of eight southern states

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

2) Confidence interval

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 98% of confidence, our significance level would be given by \alpha=1-0.98=0.02 and \alpha/2 =0.01. And the critical value would be given by:

z_{\alpha/2}=-2.33, z_{1-\alpha/2}=2.33

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.34 - 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.326

0.34 + 2.33\sqrt{\frac{0.34(1-0.34)}{6138}}=0.354

The 98% confidence interval would be given by (0.326;0.354)

8 0
2 years ago
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