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Softa [21]
2 years ago
12

In 2016, the mean score on the AP Statistics exam was 2.80, with a standard deviation of 1.35. The mean score on the AP Calculus

exam was a 2.86, with a standard deviation of 1.55. What is the combined mean and standard deviation for these exams?
Mean, 2.83; standard deviation, 0.2

Mean, 5.66; standard deviation, 2.9

Mean, 5.66; standard deviation, 2.055

Mean, 2.83; standard deviation, 2.9

Mean, 5.66; standard deviation, 4.225
Mathematics
1 answer:
Artemon [7]2 years ago
8 0

Answer:

benjamin is good 2-3x

Step-by-step explanation:

You might be interested in
Mason owns a trucking company. For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an
emmasim [6.3K]

Answer: The required system of equations are

y = 30x

13x + y = 258

Step-by-step explanation:

Let x represent the number of hours

that the driver worked.

Let y represent the number of miles that the truck drove.

For every truck that goes out, Mason must pay the driver $13 per hour of driving and also has an expense of $1 per mile driven for gas and maintenance. If on a particular day, his total expenses for the driver, gas and truck maintenance were $258, it means that

13x + y = 258

On that particular day, the driver drove an average of 30 miles per hour.

Speed = distance/time

It means that

y/x = 30

y = 30x

4 0
2 years ago
Read 2 more answers
Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what
Nana76 [90]

Answer:

Her brother catch her at 11 am + 4hour = 15 p.m  

Step-by-step explanation:

Given as ;

Speed of Ariel = 45 mph

She left home at 9 a.m

Her brother speed = 60 mph

Her brother left home at 11 a.m

Now from question So As Ariel speed is 45 mph so, after two hours pass , she ahead 90 m .

As her brother travel as 60 mph ,so he travel at ( 60 - 45 )= 15 mph faster

So, with this speed her brother will catch up her at \frac{90}{15} = after 4 hour .

Hence her brother catch her at 11 am + 4hour = 15 p.m  Answer

4 0
2 years ago
Read 2 more answers
Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)
MakcuM [25]

Answer:

The cost is $9.70 per kilogram.

Step-by-step explanation:

This can be solved by a rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:

1 pound - xkg

2.2 pound - 1 kg

2.2x = 1

x = \frac{1}{2.2}

x = 0.45kg

Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?

$4.40 - 0.45kg

$x - 1kg

0.45x = 4.40

x = \frac{4.40}{0.45}

x = 9.70

The cost is $9.70 per kilogram.

6 0
2 years ago
How many terms are in the algebraic expression -7 + 12x4 - 5y8 + x?
Mazyrski [523]

Answer:

4

Step-by-step explanation:

Each mix of numbers and letters that is separated by a + or a - is a term.

5 0
2 years ago
Clarissa needs a $2,500 loan in order to buy a car. Which loan option would allow her to pay the least amount of interest?
denis-greek [22]

Answer:

Option A.

Step-by-step explanation:

Clarissa needs a $2,500 loan in order to buy a car.

There are 4 options of loan we will calculate all the options that pay the least amount of interest.

To calculate the interest we will use this formula :

\frac{P\times R\times time}{100}

Where P = Principal amount

R = rate of interest

T = time in years

A) Principal 2,500 interest 4.75% and time 18 months (1.5 years)

\frac{2500\times 4.75\times 1.5}{100}

= $178.125

B) Principal 2,500 interest 4% and time 30 months (2.5 years)

\frac{2500\times 4\times 2.5}{100}

= $250

C) Principal 2,500 interest 4.25% and time 24 months (2 years)

\frac{2500\times 4.25\times 2}{100}

= $212.50

D) Principal 2,500 interest 4.50% and time 36 months (3 years)

\frac{2500\times 4.5\times 3}{100}

= $337.50

The least amount of interest would be in option A.

5 0
2 years ago
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