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aniked [119]
2 years ago
12

In the lab, you used the filter box in Wireshark to remove traffic from port 3389. What is that port used for? What filter synta

x could you use to show only the Ping traffic that was generated in the lab?
Computers and Technology
1 answer:
Dmitry_Shevchenko [17]2 years ago
6 0

Answer:

Port 3389 is used for remote desktop access to graphical interfaces.

The syntax used to track ping traffic is " tcp.port eq 25 or icmp".

Explanation:

Wireshark is a network packet sniffer tool used to analysing and troubleshooting packet transmission in a network.

The ping command is used in a network to check or confirm connectivity between two devices in the network. It sends ICMP message echos to the specified IP address and receives it back if there is connection. To get the ping traffic in wireshark the command syntax " tcp.port eq 25 or icmp" is used.

The port 3389 is a TCP and UDP listening port for the Microsoft proprietary protocol called remote desktop protocol or connection used to remotely connect to the graphical interface of other system running the RDP server.

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Strlen("seven"); what is the output?
Leokris [45]

Answer:

A is your answer hope this helps

4 0
2 years ago
Haley is helping to choose members for a customer satisfaction team. Which of the following employees demonstrate skill in focus
ivanzaharov [21]
Jesse constantly looks for better ways to solve problems for customers
7 0
2 years ago
(Package Inheritance Hierarchy) Package-delivery services, such as FedEx®, DHL® and UPS®, offer a number of different shipping o
lys-0071 [83]

Answer:

Check the explanation

Explanation:

note: code is implemented as per the main method provided:

code:

using System;

public class Package

{

string senderName11;

string senderAddress1;

string senderCity1;

string senderState1;

string senderZip1;

string recipientName1;

string recipientAddress1;

string recipientCity1;

string recipientState1;

string recipientZip1;

decimal weight1;

decimal costPerOunce1;

public string SenderName11

{

get { return senderName11; }

set { senderName11 = value; }

}

public string SenderAddress1

{

get { return senderAddress1; }

set { senderAddress1 = value; }

}

public string SenderCity1

{

get { return senderCity1; }

set { senderCity1 = value; }

}

public string SenderState1

{

get { return senderState1; }

set { senderState1 = value; }

}

public string SenderZip1

{

get { return senderZip1;}

set { senderZip1 = value; }

}

public string RecipientName1

{

get { return recipientName1; }

set { recipientName1 = value; }

}

public string RecipientAddress1

{

get { return recipientAddress1; }

set { recipientAddress1 = value; }

}

public string RecipientCity1

{

get { return recipientCity1; }

set { recipientCity1 = value; }

}

public string RecipientState1

{

get { return recipientState1; }

set { recipientState1 = value; }

}

public string RecipientZip1

{

get { return recipientZip1; }

  set { recipientZip1 = value; }

}

public decimal Weight1

{

get { return weight1; }

set

{

if (value > 0)

weight1 = value;

else

Console.WriteLine("Weight1 can't be less tha zero");

}

}

public decimal CostPerOunce1

{

get { return costPerOunce1; }

set

{

if (value > 0)

costPerOunce1 = value;

else

Console.WriteLine("Cost per ounce can't be less than zero");

)

{

SenderName11 = senderName11;

SenderAddress1 = senderAddress1;

)

{

TwoDayDeliveryFee = twoDayDeliveryFee;

}

public override decimal CalculateCost()

{

return base.CalculateCost() + TwoDayDeliveryFee;

}

OvernightDeliveryFeePerOunce = overnightDeliveryFeePerOunce;

}

public override decimal CalculateCost()

{

return (CostPerOunce1 + OvernightDeliveryFeePerOunce) * Weight1;

}

}

class TestPackages

{

static void Main(string[] args)

{

Package regularPackage = new Package

(

"Peter Anderson",

"123 Main St, Ashville, NC 27111 ",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St Benson, NC 27222",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M

);

Console.WriteLine("\nRegular Package: ");

  Console.WriteLine(" Sender's Name: {0}",

      regularPackage.SenderName11);

  Console.WriteLine(" Sender's Address: {0}",

      regularPackage.SenderAddress1);

  Console.WriteLine(" Recipient's Name: {0}",

       regularPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

       regularPackage.RecipientAddress1);

  Console.WriteLine(" Weight1: {0}"

, regularPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

       regularPackage.CostPerOunce1);

  Console.WriteLine("Shipping Cost: {0:C}",

       regularPackage.CalculateCost());

Console.WriteLine(regularPackage.CalculateCost());

 

TwoDayPackage twoDayPackage = new TwoDayPackage

(

"Peter Anderson",

"123 Main St 123 Main St, Ashville, NC 27111",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M,

1.5M

);

  Console.WriteLine("\nTwo-Day Package: ");

  Console.WriteLine(" Sender's Name: {0}",

  twoDayPackage.SenderName11);

Console.WriteLine(" Sender's Address: {0}",

twoDayPackage.SenderAddress1);

  Console.WriteLine(" Recipient's Name: {0}",

   twoDayPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

   twoDayPackage.RecipientAddress1);

  Console.WriteLine(" Weight1: {0}", twoDayPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

   twoDayPackage.CostPerOunce1);

  Console.WriteLine(" Flat Fee: {0:C}",

   twoDayPackage.Weight1);

  Console.WriteLine(" Shipping Cost: {0:C}",

   twoDayPackage.CalculateCost());

OvernightPackage overnightPackage = new OvernightPackage

(

"Peter Anderson",

"123 Main St 123 Main St, Ashville, NC 27111",

"Ashville",

"NC 27111",

"MN 55416",

"Mary Brown",

"456 Broad St Benson, NC 27222",

"St. Petersburg",

"Benson",

"NC 27222",

160M,

0.1M,

1.5M

);

Console.WriteLine("\nOvernight Package: ");

  Console.WriteLine(" Sender's Name: {0}",

   overnightPackage.SenderName11);

  Console.WriteLine(" Sender's Address: {0}",

   overnightPackage.SenderAddress1);

  Console.WriteLine(" Recipient's Name: {0}",

   overnightPackage.RecipientName1);

  Console.WriteLine(" Recipient's Address: {0}",

   overnightPackage.RecipientAddress1);

  Console.WriteLine(" Weight1: {0}",

   overnightPackage.Weight1);

  Console.WriteLine(" Cost Per Ounce: {0:C}",

   overnightPackage.CostPerOunce1);

  Console.WriteLine(" Additional Cost Per Ounce: {0:C}",

   overnightPackage.OvernightDeliveryFeePerOunce);

  Console.WriteLine(" Shipping Cost: {0:C}",

   overnightPackage.CalculateCost());

Console.WriteLine(overnightPackage.CalculateCost()); Console.ReadKey();

}

}

The Result can be seen below:

8 0
2 years ago
Skylar is viewing her personal and business calendar in a side-by-side fashion, but she would like to view a single calendar tha
pogonyaev

Answer:

The solution for the current situation in which Skylar is viewing her personal and business calendar in a side-by-side fashion, but she would like to view a single calendar that has appointments and meetings from both personal and business. is:

Configure the Overlay option.

Explanation:

The reasons behind this answer are that in the first place, creating another calendar is too much work. In the second place, the share of the calendars is not going to help her because that would only allow someone else to watch her calendars. However, using the overlay option will allow her to mix them and create one calendar with all her information.

8 0
2 years ago
A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

7 0
2 years ago
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