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riadik2000 [5.3K]
2 years ago
13

Which among the following enhances WS-Security to facilitate a mechanism for issuing, renewing, and validating security tokens?

Computers and Technology
1 answer:
Aleksandr-060686 [28]2 years ago
5 0

Answer:

a. WS-Trust

Explanation:

WS-Trust can be defined as a WS-specification as well as OASIS standard that help to provides extensions to WS-Security, in order to facilitate a mechanism for issuing, renewing, as well as validating of security tokens which is why the aim and objectives of WS-Trust is to help and enable applications to construct trusted SOAP message exchanges.

Nevertheless WS-Trust enables the issuance as well as the dissemination of credentials within several and various trust domains.

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Color of seagrass beds on navigational charts? Please quickly
Nadya [2.5K]
Hello! The color of seagrass beds on navigational charts are brown, because they are in shallow areas and it helps you know the locations of them.
5 0
2 years ago
____ twisted pair is the least quality twisted pair wire that should be used in a data/voice application.
xxMikexx [17]

Answer:

Category 5 (Cat 5) twisted pair is the least quality twisted pair wire that should be used.

Explanation:

The reason is as follows:

  1. Category 1 twisted pair is not suitable for transmitting data but comes in handy for telephone communications. Hence, it should not be used in a data/voice application.
  2. Category 2 twisted pair is suitable for data transmission, however, it can only transmit at 4Mbps which is very slow. Hence, it should not be used in a data/voice application.
  3. Category 3 twisted pair can transmit data with speed reaching 10Mbps which is slow for voice/data communication.
  4. Category 4 twisted pair can transmit data with speed reaching 16Mbps and is used in token ring networks. It is slow for communicating in a voice/data application.
  5. Category 5 twisted pair is the least qualified to be used in a voice/data application because it can transmit data at speeds that reach 100Mbps.

Hence, Cat 5 or Category 5 twisted pair is the least quality twisted pair that should be used in a data/voice application.

6 0
2 years ago
Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

 if(condition2) {

//executes when condition1  and condition2 evaluate to true

 }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

  if (busArrived=="yes")   {

      if (!sick)       {

          if (homework=="done")           {

              printf("Go to school.");

          }

      }     

  }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Go to school."; }

6 0
2 years ago
PLEASE HELP PROGRAMMING WILL GIVE BRAINLIEST
JulijaS [17]
The fourth choice is correct.
5 0
2 years ago
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a space. Ex: I
VARVARA [1.3K]

Answer:

import java.util.Scanner;  //mentioned in the question.

public class ArraysKeyValue {  //mentioned in the question.

public static void main (String [] args) {  //mentioned in the question.

final int SIZE_LIST = 4; //mentioned in the question.

int[] keysList = new int[SIZE_LIST]; //mentioned in the question.

int[] itemsList = new int[SIZE_LIST]; //mentioned in the question.

int i; //mentioned in the question.

keysList[0] = 13; //mentioned in the question.                                

keysList[1] = 47; //mentioned in the question.

keysList[2] = 71; //mentioned in the question.

keysList[3] = 59; //mentioned in the question.

itemsList[0] = 12; //mentioned in the question.

itemsList[1] = 36; //mentioned in the question.

itemsList[2] = 72; //mentioned in the question.

itemsList[3] = 54;//mentioned in the question.

// other line to complete the solution is as follows--

for(i=0;i<(keysList.length);i++) //Loop to access all the element of keysList array variable.

    {// open for loop braces

        if(keysList[i]>50) // compare the value of keysList array variable with 50.

        System.out.println(itemsList[i]); // print the value

   }// close for loop braces.

}//  close main function braces.

} //close the class braces.

Output:

72

54

Explanation:

In the solution part--

  1. One loop is placed which moves from 0 to (size-1) of the 'keyslist' array.
  2. Then the 'if' statement is used to check the element of 'keyslist' array, which is greater than 50 or not.
  3. If it is greater, then print the element of item_list array of 'i' index which is also the index of greater value of keyslist array element.

5 0
2 years ago
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