Question

The volume V, in liters, of air in the lungs during a four-second respiratory cycle is approximated by the model V = 0.1729t + 0.1522t2 − 0.0374t3, where t is the time in seconds. Approximate the average volume of air in the lungs during one cycle. (Round your answer to four decimal places.)

Answer 1

It was stated that the respiratory cycle takes 4 seconds. So, you just have to simply substitute t=4 to the equation to find the average volume of air in the lungs per cycle.

$V =0.1729t+ 0.1522t^{2} -0.0374 t^{3}$

$V =0.1729(4)+ 0.1522(4^{2}) -0.0374 (4^{3} )$

V = 0.7332 liters of air in one cycle

Answer 2

Answer:

0.7296 liters

Step-by-step explanation:

The volume of air in the lungs during a four seconds respiratory cycle is approximated by the model by

V = 0.172 (4) + 0.1522 (4)² - 0.0374 (4)³

  =  0.688 + 2.4352 - 2.3936

  = 0.7296 liters

Therefore, average volume of the air in the  lungs in one cycle is 0.7296 liters.