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tiny-mole [99]
2 years ago
8

A grocery store manager must decide how to best present a limited supply of milk and cookies to its customers. Milk can be sold

by itself for a profit of $1.50 per gallon. Cookies can likewise be sold at a profit of $2.50 per dozen. To increase appeal to customers, one gallon of milk and a dozen cookies can be packaged together and are then sold for a profit of $3.00 per bundle. The manager has 100 gallons of milk and 150 dozen cookies available each day. The manager has decided to stock at least 75 gallons of milk per day and demand for cookies is always 140 dozen per day. To maximize profits, how much of each product should the manager stock.Which of the following is the objective function for the grocer's problem?A) Max P = 1.5M + 2.5C + 3BB) Min P = 1.5M + 2.5C + 3BC) Max P = 2.5M + 1.5C + 3BD) Max P = 2.5M + 3C + 1.5BE) Min P = 1.5M + 1.5C + 3B
Mathematics
1 answer:
miss Akunina [59]2 years ago
7 0

Answer:

Option A.

Step-by-step explanation:

Let M be the milk per gallon.

C be the cookies per dozen.

B be the bundle (one gallon of milk and a dozen cookies ).

Milk can be sold by itself for a profit of $1.50 per gallon. Cookies can likewise be sold at a profit of $2.50 per dozen and bundle is sold for a profit of $3.00 per bundle.

Profit= 1.5M + 2.5C + 3B

We need to maximize the profits. So, our objective function is

Therefore, the correct option is A.

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Answer:

The meet at first time at starting point after 336 seconds,

Vanu have completed 7 laps while Tanuj has completed 6 laps.

Step-by-step explanation:

Given that Venu and Tanuj take 48 seconds and 56 seconds to

complete a lap respectively.

To meet them again at the startiong point, the  time taken must be multiple of 56 and 48.

So, the minimum time required to meet them again at the startiong point is time taken for first time meet.

Time taken to first time meet is the smallest number which can be divided by 56 and 48, i.e the lowest common factor (LCM) of 56 and 48 which is 336 seconds or 5 minutes 36 seconds.

Number of laps by Venu

=\frac{336}{48}=7

Number of laps by Tanuj

=\frac{336}{56}=6

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2 years ago
How many repeating digits are in 0.ModifyingAbove 536 with bar? 1 2 3 4
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Answer:

3

Step-by-step explanation:

We want to determine the number of repeating digits in 0.\overline{536}

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The third choice is correct

5 0
2 years ago
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∠1 = 50°
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Now multiply each value of 3568 with the values of 39610. Like:

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Part A: Growing

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Part C: 8100

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