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krok68 [10]
2 years ago
4

Given ΔFGH ~ ΔLMN, which must be true? Select all that apply.

Mathematics
1 answer:
Taya2010 [7]2 years ago
5 0
Answers are: B, E, D
You might be interested in
A good indicator of the value of a company is the ratio of the price of its stock to its yearly earnings expressed as dividends.
gulaghasi [49]

Answer:

4.92 cents

Step-by-step explanation:

The Price to Earnings or P/E is the ratio of the price of its stock to its yearly earnings expressed as dividends.

The price of a stock is $36 and it's earnings are $3.00

This means the price to earnings ratio,

P/E = 36/3 = 6

Let us express this ratio as percentage. This becomes

36/3 ×100 = 1200%

This means the ratio of price to earnings = 1200%

For an increase of 20%, the ratio of price to earnings will be = 1200 + 20 = 1220%.

Let x be the the value of earnings that would increase the ratio by 20%

36/3 × 100 = 1200%

36/x × 100 = 1220℅

3600/x = 1220

x = 3600/1220 = $2.9508

The amount by which the earnings must decrease in order that the P/E ratio increases by 20% will be

$3 - $2.9508 = $0.0492.

Converting to cents, we multiply by 100. It becomes

0.0492×100 = 4.92 cents

3 0
2 years ago
Callan goes for a hike every Saturday. Callan hikes at a rate of three miles per hour.
ioda

Answer:

I believe its

1. 3

3. 9

5. 15

5 0
2 years ago
Read 2 more answers
The triangles are congruent by the SSS congruence theorem. Which rigid transformation(s) can map MNP onto TSR? Reflection only r
ElenaW [278]

Answer:

the answer here is C) translation, then reflection

Step-by-step explanation:

if you translate point P to point R and then translate across that point they map onto each other


7 0
2 years ago
Read 2 more answers
A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials . The cameras sell
kobusy [5.1K]
A) set x as the number of cameras
18x=9x+1800
9x=1800
x=200

b) i'm assuming it's increasing production from my answer in a, so the profit would be 18(250)-(9*250+1800)=4500-4050=450
4 0
2 years ago
Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number
Masja [62]

Answer:

<h2>√512 by √512 </h2>

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y²  = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m  by √512 m

5 0
2 years ago
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