Question

A diploid organism has 10 total chromosomes (2n=10). A cell from this organism has 5 total chromosomes and 10 double-helical DNA molecules. This cell could be at which of the following stages of cell division?
prophase of meiosis I
metpahse of meiosis II
anaphase of meiosis II
telophase of meiosis I before cytokinesis
metaphase of meiosis I
G1
G2
telophase of meiosis II before cytokinesis
anaphase of meiosis I

Answer 1

In metaphase, anaphase and telophase of meiosis 2 before cytokinesis the condition prevails.

Explanation:

Meiosis is the type of cell division which takes place in the gamete mother cells to produce gametes. Its a reduction division because the germ mother cells are diploid and gametes are haploid.

In the cells undergoing the meiotic cell division, the cells at first undergo DNA replication which make the DNA content of each chromosome doubled.

Then through meiosis 1, the cell undergo the reduction division which makes the diploid cell haploid. So here the cell with 10 chromosomes become cell with 5 chromosome. But the DNA content per chromosome remains doubled. This is restored by the second meiosis division where the chromosome becomes divided into chromatids with normal DNA amounts.

So in every steps of meiosis 2, untill the cytokinesis is achieved, the cell remains in the haploid yet double DNA amount condition.