Answer: Primary Research (Focus Group).
Explanation:
Exploratory Research is an inquiry that seeks to understand the basic causal factors of a problem. This effort can serve as the basis of more intensive research later on.
There are basically two methodologies used, which are the; Primary and Secondary methods. While the Primary method's source of information is the concerned group, the Secondary Methods obtain their information from already existing information (Primary sources), such as Interviews, Journals, etc.
In the case of the company in the question, seeking to gain insight into the changes in a product, it would be best for them to consider what some selected costumers (focus group), think about the existing products and their views on subsequent changes. This method of getting information directly from the focus group employs the primary method.
Answer:
a. grep 'b[au]nk$' myLine
Explanation:
grep is a command used for searching a specified pattern in a given text.
Our goal is to match the character sequence - bank or bunk at the end of line in a given line referenced by myLine.
The regular expression for the specified match criterion is:
b[au]nk$
The second character can be either a or u.
$ indicates match at end of line.
So the overall grep command is :
grep 'b[au]nk$' myLine
You said it in your question. The case! Though it's also given other names, such as housing, chassis, enclosure etc.
Answer:
The code is given below
Explanation:
The correct syntax would be to place appropriate parenthesis.
(month==1?"jan":(month==2?"feb":(month==3?"mar":(month==4?"apr":(month==5?"may":(month==6?"jun":(month==7?"jul":(month==8?"aug":(month==9?"sep":(month==10?"oct":(month==11?"nov":"dec")))))))))));
Similarly, you can also use the following code:
String[] months = { "jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec" };
int month = 1;
String monthDescription = months[month - 1];
Answer: see description
Explanation:
first we accommodate the bit pattern in a matrix of 4x4 which is the minimum length checksum field, now with even parity two-dimensional scheme we need to complete this matrix by adding one row and one column by adding at the end of each row a 1 or a 0 to complete pairs of 1's:
we have
![\left[\begin{array}{cccc}1&1&1&0\\0&1&1&0\\1&0&0&1\\1&1&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%260%5C%5C0%261%261%260%5C%5C1%260%260%261%5C%5C1%261%260%261%5Cend%7Barray%7D%5Cright%5D)
so we complete with this, adding a row at the end which matches a pair number of 1's
![\left[\begin{array}{ccccc}1&1&1&0&1\\0&1&1&0&0\\1&0&0&1&0\\1&1&0&1&1\\1&1&0&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%261%261%260%261%5C%5C0%261%261%260%260%5C%5C1%260%260%261%260%5C%5C1%261%260%261%261%5C%5C1%261%260%260%260%5Cend%7Barray%7D%5Cright%5D)
