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astra-53 [7]
2 years ago
15

Kendall receives an email stating that a leading computer company is giving away free computers, asking her to forward the email

to 20 of her closest friends. What should Kendall do?
Computers and Technology
1 answer:
gavmur [86]2 years ago
8 0

Explanation:

Kendall should report the email as scam and delete email instead of forwarding it. She should also run her virus protection software as these kind of emails on the Internet are mostly Fraud and can contain virus so the user should avoid them.

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To keep from overwriting existing fields with your Lookup you can use the ____________ clause.
Radda [10]
I believe the answer is <span>outputnew
</span>The main difference between the output new and the output is that outputnew won't overrite the alredy existing description field.
If you don't put this clause, <span>Splunk would adds all the field names and values to your events by through the lookup.</span>
3 0
1 year ago
Read 2 more answers
The c++ operator _______________ is used to destroy dynamic variables.
UNO [17]
<span>The c++ operator delete is used to destroy dynamic variables.</span>
6 0
2 years ago
Define the instance method inc_num_kids() for PersonInfo. inc_num_kids increments the member data num_kids. Sample output for th
kow [346]

Answer:

This is the instance method inc_num_kids()

def inc_num_kids(self):

       self.num_kids += 1

Explanation:

The first line is the definition of function inc_num_kids() which has a parameter self. self is basically an instance of  class PersonInfo

self.num_kids += 1 this statement incremented the data member num_kids by 1. This means that the instance method inc_num_kids, using instance self, increments the value of num_kids data member by 1.

The complete program is as following:

class PersonInfo:  #class name PersonInfo

   def __init__(self):   #constructor of the class

       self.num_kids = 0  # data member num_kids

   def inc_num_kids(self):  # method inc_num_kids

       self.num_kids += 1  #increments num_kids by 1

person1 = PersonInfo()  #creates object person of class PersonInfo

print('Kids:', person1.num_kids)  # prints num_kids value before increment

person1.inc_num_kids()  #calls inc_num_kids method to increment num_kids

print('New baby, kids now:', person1.num_kids) #prints the value of num_kids after increment by inc_num_kids method

The person1 object first access the initial value of num_kids initialized by the constructor. So the first value of num_kids is 0. self.num_kids = 0  This statement assigns the value 0 to num_kids data member. Next the method inc_num_kids() using the object person1. Now when this method is called the value of data member num_kids is incremented to 1.

So previously the value was 0 which now increments by 1 and becomes 1. Last print statement displays this new value which is incremented by the inc_num_kids() method.

Hence the output is:

Kids: 0

New baby, kids now: 1

The program along with its output is attached.

7 0
2 years ago
Which DFS option can be used to help manage peak bändwidth needs by forcing replication to occur during off hours?
andrey2020 [161]

Answer: D. Scheduling

Explanation:

Distributed file system (DFS) replication scheduling are used most especially when large files need to be replicated across lower bandwidth connections. It helps manage peak bandwidth by forcing replication to occur during off hours

5 0
1 year ago
) Consider a router that interconnects four subnets: Subnet 1, Subnet 2, Subnet 3 and Subnet 4. Suppose all of the interfaces in
erik [133]

Answer:

Check the explanation

Explanation:

223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.

The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000

Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)

So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26

Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)

and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25

Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)

So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28

4 0
1 year ago
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