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Vera_Pavlovna [14]
2 years ago
9

Alika finds a certain kind of butterfly near her house. She reads that ultraviolet light is absorbed by the butterfly's wings, r

ed light is transmitted through the butterfly's wings, and green light is reflected off the butterfly's wings. Alika's friend Claire tells her that if you shine light on the butterfly, its wings will glow. Can light cause the butterfly's wings to glow? Why or why not? Does it matter what type of light Alika shines on the butterfly?
Biology
1 answer:
Helga [31]2 years ago
5 0

Answer:

No, light can't cause the butterfly's wing's to glow.

Explanation:

Butterflies contain wings which are of different colors for attractiveness and also to show warning alarm for it's predator. They are attracted to light but they can't absorb sun light.

Their wings contain scales that are of different color.

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What current will an ammeter register if 960C of charge flow through it in 2 minutes?
postnew [5]

Answer:

8A

Explanation:

I= Q/t, where

I= current (A)

Q= charge (C)

t= time (s)

First convert the time from minutes to seconds.

1 minute= 60 seconds

2 minutes= 2×60= 120 seconds

Using the formula,

I= 960÷120

I= 8A

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2 years ago
The Punnett square for a non-freckled parent and a homozygous freckled parent is shown below. What is the probability that their
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A ligand produces a response in a cell if it finds the right kind of
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2 years ago
Y-: yellow S-: star yy: black ss: starless
Ede4ka [16]

Answer:

1. heterozygous yellow and star

2. 37

3. 1/8

4. 168

5. 1/4

Explanation:

Given ,

In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch

yySS x YYss

It is taken as - Y (yellow) is dominant over y (black)

and S (star) is dominant over s (starless)

1. F1 Generation

Genotype of parents yySS X YYss

gametes - yS, yS, Ys, Ys

All 16 offspring will have genotype YySs

phenotype would be heterozygous yellow and star

2. F2 generation cross

YySs X YySs

YS        Ys         yS        ys

YS YYSS YYSs YySS YySy

Ys YYSs YYss YySs Yyss

yS YySS YySs yySS yySs

ys YySs Yyss yySs yyss

Genotype of offspring are –  

YYSS – 1

YYSs – 2

YySS – 2

YySs – 4

YYss- 1

Yyss- 2

yySS – 1

yySs- 1

yyss- 1

2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches

So out of 300, 37 are black star bellied sneetches

3. Only 2 out of 16 are true breeding. i.e 1/8

4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches

5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding

7 0
2 years ago
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