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Answer: C. Squamous epithelial tissue.
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The answer is 49.92%
Let's use the <span>Hardy-Weinberg principle:
p + q = 1
p</span>² + 2pq + q² = 1
<span>
where:
p - the frequency of dominant allele G
q - </span>the frequency of recessive allele g
p² - the frequency of homozygous dominant individuals GG with colour green
2pq - the frequency of heterozygous individuals Gg with colour green
p² - the frequency of homozygous recessive individuals gg with color brown
23% of the population is brown: p² = 23% = 0.23
p = √(p²) = √0.23 = 0.48
p = 0.48
p + q = 1
0.48 + q = 1
q = 1 - 0.48 = 0.52
<span>The percentage of the population that is expected to be heterozygous is 2pq:
2pq = 2 * p * q = 2 * 0.48 * 0.52 = 0.4992 = 49.92%</span>
Hi, The center image is a decomposer because it decomposes the dead organisms. The grass is a producer since it produces its own energy through photosynthesis. The rest are consumers because they consume other organisms to get energy. Hope that helped!
The safe steps in cooking, food handling, and storage are important to prohibit foodborne ailments. One cannot taste, smell, or see the harmful bacteria, which may result in illness.
In every step of food preparation, there is a need to follow the four steps of the Food Safe Families campaign to maintain the safety of food. These are clean, separate, chill, and cook.
In the given case, there is a need to cool the soup correctly in a cooler or fridge, and then reheating it on the stove at about 165 degrees F within two hours.
