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zvonat [6]
2 years ago
6

A train is leaving in 11 minutes and you are one mile from the station. Assuming you can walk at 4mph and run at 8mph, how much

time can you afford to walk before you must run in order to catch the train?
Mathematics
1 answer:
ddd [48]2 years ago
6 0

7 minutes is the time can you afford to walk

<em><u>Solution:</u></em>

Given that, train is leaving in 11 minutes and you are one mile from the station

Let "x" represent how much time can you afford to walk

Then, (11 - x) is the time you run

You can walk at 4mph and run at 8mph

<em><u>Convert to miles per minute</u></em>

1 hour = 60 minutes

4\ mph = 4 \times \frac{1}{60} \text{ miles per minute } = \frac{1}{15} \text{ miles per minute }\\\\8\ mph = 8 \times \frac{1}{60}\ \text{ miles per minute } = \frac{2}{15} \text{ miles per minute }

We know that,

Distance = speed \times time

Given that, you are one mile from the station

Therefore,

1 mile = distance walk + distance run

1 = x \times \frac{1}{15} + (11-x) \times \frac{2}{15}\\\\1 = \frac{1}{15}(x + 2(11-x))\\\\1 = \frac{1}{15}(x + 22 - 2x)\\\\x + 22 - 2x = 15\\\\x = 22 - 15\\\\x = 7

Thus, 7 minutes is the time can you afford to walk

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Chuck has a gross pay of $815.70. His gross pay will be reduced by:

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Let's count:

1. gross pay of $815.70 - 100%,

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Then

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\dfrac{815.70}{y}=\dfrac{100}{1.45} ,\\ \\815.70\cdot 1.45=y\cdot 100,\\ \\y=\dfrac{815.70\cdot 1.45}{100} =11.82765.

3. Federal tax of $56 - 100%,

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\dfrac{56}{z}=\dfrac{100}{19} ,\\ \\56\cdot 19=z\cdot 100,\\ \\z=\dfrac{56\cdot 19}{100} =10.64.

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\$56+\$50.5734+\$11.82765+\$10.64=\$129.04105\approx \$129.04.

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∵ Line TW intersects line SV at R

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\angle DBC=40°

From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

m\textrm{ arc CD}=2\times \angle DBC\\m\textrm{ arc CD}=2\times 40=80

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

m\angle BCD=90

From the Δ BCD, which is a right angled triangle,

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