Question

Take a factor out of the square root: 48x^2 , where x≤0

Answer 1

Answer: $4/x/\sqrt{3}$

Step-by-step explanation:

$\sqrt{48x^{2} }$

this could also be written as :

$\sqrt{48}$ x $\sqrt{x^{2}}$

$\sqrt{x^{2}}$ = ±$x$ , so we have

$\sqrt{48}/x/$

$\sqrt{48}$ could be written as: $\sqrt{16}$ x $\sqrt{3}$

which will result into $4\sqrt{3}$

combining all together , we have

$4/x/\sqrt{3}$

Therefore , one of the factor of $\sqrt{48x^{2} }$ is $4/x/\sqrt{3}$