The answer to this question is "to monitor all the elements of the marketing mix for a Oregon winery". This is the main task of the tuna marketer's task in the emailing or website which is very known s tunwonderfish.com and this compaign was exclusively related to the elements of mixing in a large Oregon winery but not including the production.
Answer:
The program to this question can be given as follows:
Program:
//class
public class factorial //defining class
{
//method fact
public static long fact(int x1) //defining method fact
{
//conditional statement
if (x1 <= 1) //if block checks parameter value less then equal to 1
{
return 1; //return value
}
else //else part
{
return (fact(x1 - 1) * (long) x1); //return factors using recursive function
}
}
//method main
public static void main(String[] args) //defining main method
{
long data=fact(5);//defining variable that holds function value
System.out.println("Factorial is: "+data); //print value
}
}
Output:
Factorial is: 120
Explanation:
In the above java program, a class is "factorial" is defined, inside the class, a static method "fact" is declared, that accepts an integer parameter that is "x1" and returns a long value, inside this method a conditional statement is used.
- If the block it checks parameter value is less then equal to 1, if this condition is true, it will return 1 when this condition is not true. It will go in else part.
- In else part, it uses a recursive function to calculate factorial of a number and return its value.
- Then the main method is defined, inside this method a long variable "data" is defined, that call and holds fact function return value, and in the next line, the print function is used to print the data variable value.
Answer:
b) Bounded Waiting
Explanation:
int currentThread = 1;
bool thread1Access = true;
bool thread2Access = true;
thread1 { thread2 {
While (true) {
While (true)
{
while(thread2Access == true)
{
while(thread1Access == true)
{
If (currentThread == 2) {
If (currentThread == 1)
{
thread1Access = false; thread2Access = false;
While (currentThread == 2);
While (currentThread == 1);
thread1Access = true; thread2Access = true;
} }
/* start of critical section */ /* start of critical section */
currentThread = 2 currentThread = 1
… ...
/* end of critical section */ /* end of critical section */
thread1Access = false; thread2Access = false;
… ...
} }
} }
} }
It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.
Answer:
stress about paying bills
a lack of money for other expenses
great electronic connectivity
Explanation:
The Maya classic period has seen the rise of conspicuous and mass consumption. In the given scenario all the expense her paid by credit cards and cash is rarely used. There will be a stress for paying bills. There will be lack of money available in hand for some routine expenses and mandatory purchases. It gives a great electronic connectivity. All the funds are considered as safe.
Answer:
An eye for detail and good visualization skills.
Explanation:
In which job role would a course in 3D modeling help with professional career prospects? Computer Programmer. Multimedia Artist. Technical Support Specialist.
