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Komok [63]
2 years ago
12

At a track meet, Samma finished the 200-meter race in 25.98 seconds. Tom finished the 100-meter race in 12.54 seconds. Which run

ner ran at a faster average rate?
Mathematics
2 answers:
Varvara68 [4.7K]2 years ago
6 0
They have the same time average because if tom ran the 200 mile race he would have double his time on the 100 meter race. 12.54 x 2= 25.98 seconds, so they have the same average rate.
andrezito [222]2 years ago
6 0

Answer: Tom ran at a faster average rate.

Step-by-step explanation:

Given: Samma finished the 200-meter race in 25.98 seconds.

The average rate of distance traveled by Samma is given by :-

\text{Average rate}_1=\frac{\text{Distance}}{\text{time}}=\frac{200}{25.98}\\\Rightarrow\text{Average rate}_1=7.698229407\approx7.70

Tom finished the 100-meter race in 12.54 seconds.

The average rate of distance traveled by Tom is given by :-

\text{Average rate}_2=\frac{\text{Distance}}{\text{time}}=\frac{100}{12.54}\\\Rightarrow\text{Average rate}_2=7.97448165\approx7.97

Clearly on comparing decimal places, we get 7.97>7.70

Hence, Tom ran at a faster average rate.

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nasty-shy [4]

Answer:

The measure of angle JKL is 97 degrees.

Step-by-step explanation:

Given:

A triangle JKL .

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Note:

Linear pair angles sum is 180 degree.

Let \angle JKL be 'x' degrees .

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⇒ <em>Subtracting 83 from both sides.</em>

⇒ x+83-83=180-83

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⇒ x=97 degrees

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