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Ray Of Light [21]
2 years ago
8

An online music store sells about 4000 songs each day when it charges $1 per song. For each $0.05 increase in price, about 80 fe

wer songs per day are sold. Use the verbal model and quadratic function to determine how much the store should charge per song to maximize daily revenue. R(x)=(1+0.05x)(4000-80x)
Mathematics
2 answers:
Anna71 [15]2 years ago
8 0
X is the number of $0.05 price increases 
<span>so </span>
<span>15 × 0.05 = $0.75 </span>
<span>and so, walla, (0.75, 4900) </span>
<span>or </span>
<span>increase price by $0.75 for max profit of $4900. </span>

<span>otherwise your math was sound</span>
Shkiper50 [21]2 years ago
5 0

Answer:

The best price is $1.75.

Step-by-step explanation:

Profit = Songs x Price  

Given equation is ;

R(x)=(1+0.05x)(4000-80x)

Solving this :

Let the number of $0.05 increases be x.

R(x) = -4x^{2}+120x+4000

The revenue is maximized when dR/dx = 0.  

dR/dx = -8x+120

The revenue is maximized when x = 15

Means when the price per song = $1.00 + ($0.05*15) = $1.75

Therefore, the best price is $1.75.

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2 years ago
Three times the sum of half Carlita's age and 3 is at least 12. What values represent Carlita's possible age?
cestrela7 [59]

Answer:

at least 6

Step-by-step explanation:

3(.5x+3)>12

1.5x+9>12

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2 years ago
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Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

Also  

    \frac{CA}{sin (32)} =  \frac{467.3 }{sin (107.8)}

    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

4 0
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An architect designs a rectangular flower garden such that the width is exactly two thirds of the length of 270 feet of an antiq
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Answer:

15.6%

Step-by-step explanation:

Since each day there is a 6% chance that Lisa smiles at him then that means that each day there is a 94% chance that Lisa does not smile at him. To find the probability of Milhouse going longer than a month (30 days) without a smile from Lisa we need to multiply this percentage in decimal form for every day of the month. This can be solved easily by putting 94% to the 30th power which would be the same, but first, we need to turn it into a decimal...

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Now we can turn this decimal into a percentage by multiplying by 100

0.156 * 100 = 15.6%

Finally, we can see that the probability that Milhouse goes longer than a month without a smile from Lisa is 15.6%

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