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Daniel [21]
2 years ago
3

Marco is limited to 7 hours of screen time each week. he decides to watch a movie that is 1 hour and 20 minutes on sunday. if he

divides the remainder of time equally amongst the other six days, then how many minutes can h.e watch each day? write and solve an inequality.
​
Mathematics
1 answer:
stich3 [128]2 years ago
8 0

Marco can watch TV for at most 56 minutes each day.

Step-by-step explanation:

Given,

Time of screen each week = 7 hours

1 hour = 60 minutes

7 hours = 60*7 = 420 minutes

Length of movie = 1 hour + 20 minutes = 60 + 20 = 80 minutes

Time left for other days = 420 - 80 = 340 minutes

Number of days = 6

Let,

x be the time per day for remaining 6 days.

Number of days * Time per day ≤ Time remaining

6x\leq 340

Dividing both sides by 6

\frac{6x}{6}\leq \frac{340}{6}\\x\leq 56.66

Marco can watch TV for at most 56 minutes each day.

Keywords: inequality, division

Learn more about division at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

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A matrix contains 60 elements. Which of the following cannot equal the number of rows of the matrix?
avanturin [10]

<span>Given:

Matrix = 60 elements</span>

 

<span>To solve this, we need to take into account that each row must contain the same number of elements. So, we need to find which of the options do not divide evenly into 60 (the options are 30, 60, 10, and 18).

So we check each of the choices to see if 1 of them divides evenly with 60.

60 / 60 = 1 (divides evenly)</span>

60 / 30 = 2 (divides evenly)

<span>60 / 10 = 6 (divides evenly)
</span>60 / 18 = 3.3.3333333333333333333333333333333 (does not divide evenly)

Therefore, 18 cannot equal the number of rows of the matrix.

6 0
2 years ago
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin
Artemon [7]

Answer:

(a) \frac{dy}{dt}=-3\frac{3}{4}

(b) \frac{dx}{dt}=3\frac{3}{4}

Step-by-step explanation:

x^{2} +y^{2}=25

Take \frac{d}{dt} of of each term.

\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\

For Question a

2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

Given that x = 3, y = 4, and dx/dt = 5.

\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\   \\\frac{dy}{dt}=-3\frac{3}{4}

For Question b

2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}

Given that x = 4, y = 3, and dx/dt = -5.

\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\   \\\frac{dx}{dt}=3\frac{3}{4}

5 0
2 years ago
Perry, maria, and lorna are painting rooms in a college dormitory. working alone, perry can paint a standard room in 3 hours, ma
Leviafan [203]

Answer:Perry and Lorna take the maximum time and Maria and Lorna take the minimum time when they work together.

Explanation: Since, according to the question- Perry takes time when he works alone = 3 hours

Similarly, Maria takes = 2 hours, While Lorna takes= 2 hours 30 minutes or 2.5 hours.

since, there are three people thus their are three possibility to choose any two of them.

1- when Perry and Maria work together then time taken by them is \frac{1}{1/2+1/3}=\frac{1}{5/6}= 6/5= 1 hour 12 minutes.

2- when Maria and Lorna work together then time taken by them is \frac{1}{1/2 + 1/2.5}= 10/9= 1 hours 1/9 minutes ≈ 1 hours 7 min

3- when Perry and Lorna work together then time taken= \frac{1}{1/3+1/2.5}= 15/11= 1 hour 4/11 minutes≈ 1 hours 21 minutes

From the above explanation, it has been proved that when we talk about 2 members team then Perry and Lorna take the maximum time. While Maria and Lorna take the minimum time when they work together.


3 0
2 years ago
Read 2 more answers
Consider the experiment of tossing a coin twice.
MAXImum [283]

Answer:

Kindly check explanation

Step-by-step explanation:

Experiment of tossing a coin twice :

A.) Experimental outcome:

Head = H ; Tail = T ;

Head and Head = HH

Tail and Tail = TT

Head and Tail = HT

Tail and Head = TH

Number of head(s) on toss = z

C)

Experimental outcome ___number of heads(z)

HH _____________________2

TT _____________________ 0

TH _____________________ 1

HT _____________________ 1

D) the random variables defined are discrete because they are only take up integer values within a specified range

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Goshia [24]

Answer:

Distance from point (0,1,1) to the given line is zero.

Step-by-step explanation:

Given parametric equations of line,

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y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x

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\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0

Distance between point (0,1,1) and (1) is zero. That is point 90,1,1) is lies on the line (1).

8 0
2 years ago
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