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2 years ago

A student made a model of an ecosystem inside a sealed plastic bottle. She

Biology

1 answer:

Anton [14]2 years ago

4 0

It illustrates the cycling of matter, just like in a natural ecosystem.

Option D.

<h3><u>Explanation:</u></h3>

The natural stable ecosystem is defined as the ecosystem which has the members doing their part of job and each and every member contribute to the stability of the ecosystem by completing food chains.

Here in this bottle ecosystem the boy put the stones, rocks, water which gives proper nutrition to the growing plants and animals which are also introduced by the boy. The plants produce oxygen and consume carbon dioxide whereas the animals consume oxygen and produce carbon dioxide. Thus the cycle is maintained and stability is achieved.

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Please help asap the scientific name Canus nipponicus. To which classification levels does this scientific name belong?

Amiraneli [1.4K]

The correct answer is - C. genus and species.

The final scientific name of an animal represents two things, its genus, and its species.

The first name is the genus of the animal, in this case we have Canus. The second name is the species of the animal, in this case nipponicus.

All living organisms are classified in a same manner: kingdom, phylum, class, order, family, genus, species.

Since the name Canus reminds me a lot of Canis, I will take the wolf as an example:

Kingdom: Animalia

Phylum: Chordata

Class: Mammalia

Order: Carnivora

Family: Canidae

Genus: Canis

Species: C. Lupus

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One critical observation used by both Lamarck and Darwin in their research is about characteristics of inheritance. Although each claimed different sources of inheritance, they were in unison that in time, individuals acquire characteristics called inheritance. Lamarck believed that inheritance is passed from parents to offspring, while Darwin thought that it’s a product of natural selection.

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a species of rodent can either have brown fur or white fur. Brown fur is recessive and white fur is dominant. what would cause t

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The mutation as the Hardy- Weinberg equation assumes that there would be no evolutionary pressures such as mutations. Hardy- Weinberg represents an 'ideal' where the allele frequencies would remain constant

The rodents mutate the new grey allele.

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What factor creates the most difficulty in predicting the possible consequences of different control methods? a. species interac

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The state of health and functioning of the liver is often assessed with dye-tracer techniques. The dye used most frequently is b

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Answer

1.Radioactive or chemical decay

2. X(t) = Xoe^-kt

lnY(t) = -t + lnYo

4. 6.07mg

Explanation:

Let the liver and and blood compartment be represented by the symbol L and B respectively

For the liver

Suppose a first Order removal process started with an amount X, in which amount b disappeared in time t, the process is decay process which can be represented as follows,

∫dX/dt = -K1X

By rearrangement and integration;

∫dX/X = -K1t

ln X = -K1t + C

Since At t= 0, X = Xo then

C = lnXo

The equation becomes:

lnX = -K1t + lnXo

lnX - lnXo = -K1t

ln(X/Xo) = -K1t

X/Xo = e^-kt

X(t) = Xoe^-kt

X(t) = Xoe^-0.5t........(2)

Similarly for B (blood), suppose a first order flow flow of the dye move from the blood to the liver, let Y be the initial concentration, and amount b that has flown to the liver in time t

B---------> B(t)

t=0 Yo 0

t=t. Y-b. b

dY/dt = -K12(Y-b)...........(3)

Let Y-b = Y(t)

∫dY/dt = -∫K12t

By rearrangement and integration;

∫dy/Y(t) = ∫-K12dt

lnY(t) = -K12t + C1

at t= 0, C1 = ln(Yo)

Therefore ln Y(t) = -K12t + lnYo

But K12 =1

ln Y(t) = -t + lnYo.............(4)

(3) The assumptions used here

is that of a decay for the liver . The amount remaining taking as the amount of a substance

(4) using the equation 2,

X(t)= Xo e^-K1t........(2)

For time t = 1hour, and an initial amount X = 10mg, K = 0.5

X(t) = 10× e^-0.5

X(t) = 10 × 0.607

X(t) = 6.07mg

(5) within the scope of information presented, I have no data to make this judgment.

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2 years ago