In eukaryotes, <em>replication takes place in the nucleus</em> as prokaryotes do not have a true nucleus and <em>replication takes place in the cytoplasm</em>. The nucleus of the eukaryotes is the location where genetic material (DNA) is found; in prokaryotes, the genetic material is condensed in the cytoplasm called the nucleoid. There are multiple replication forks or <em>multiple origins of replication </em>in eukaryotes in contrast to prokaryotes which only has <em>one origin of replication. </em>Lastly, replication in eukaryotes <em>occurs at multiple points along the chromosome; </em>in contrast with prokaryotes where it <em>occurs at just one point on the chromosome.</em>
The correct answer is: The nuclear envelope is continuous with the endoplasmic reticulum
The nuclear envelope or nuclear membrane is composed of two phospholipid bilayers (outer and inner) that surround the nucleus in the eukaryotic cell. The space between the outer and inner membranes is called the perinuclear space. The nuclear envelop has nuclear pores that are responsible for the transport between nucleus and cytoplasm (e.g. transport of mRNA).
When a stimulus is being detected, this stimulus is being sent to the brain through the sensory neuron, going to the spinal cord then to the brain. The brain then interprets these stimuli, and responds to it using the motor neurons. These are the neurons that are responsible in our actions depending on the stimuli we are exposed to. Hope this helps.
the answer to your question is the amount of time and the effect it has on each material as well as the fact that the nitrogen cannot change it is an unchangeable variable whereas everything else the time, the substance of the subject, the possible formation of nodules can change without changing the identity of the experiment itself otherwise, you have a dependent variable. I hope this helps :-)
Answer:
Strain Presence of Lactose Absence of Lactose
(+) (-)
For the wild type case, the lacZ gene product will be expressed in the presence of lactose only.
(-) (-)
Because of the super repressor, transcription will not take place regardless of the presence of lactose.
(+) (+)
The constitutive operator will allow for transcription to occur, whether or not lactose is present.
(+) (+)
The repressor is non-functional, transcription will occur with or without presence of lactose.
(+) (+)
The super repressor will not be able to stop transcription as it cannot bind to the constitutive operator.
(-) (-)
The promoter is non-functional, transcription will not start and hence, not gene product formed.
(-) (with glucose present) (-)
E. coli will not metabolize lactose in the present of glucose, since glucose is the preferred source of nutrition.
Hope that answers the question, have a great day!