Answer:
The correct option is D. <u>The chemical bond breaks between the second and third phosphate groups.</u>
Explanation:
Adenosine phosphate (ATP) can be described as main energy-carrying molecules which are required by each cell to carry out its normal functions.
A molecule of ATP comprises of the nitrogenous base Adenine, pentose sugar ribose and three molecules of phosphate.
The bond between the second and third molecule carries high amounts of energy. When this bond is broken, huge amounts of energy is released which is used by the cells to carry out essential processes.
Answer:
In C3 photosynthesis, the reactions that require ATP take place in
B) the Calvin cycle alone.
Explanation:
In C3 PLANTS PHOTOSYNTHESIS OCCUR IN TWO STEPS-
1. LIGHT stage , WHICH TAKES PLACE IN LIGHT. In this stage water is split and ATP is released.
2. DARK stage, which takes place in dark. This the stage where calvin cycle takes place which require ATP, i.e energy. In this process sugar is produced with help of carbon dioxide. In this carbon dioxide is accepted by 5- carbon molecule ribulose-1, 5-biphosphate, which result into two molecules of 3- phosphoglycerate. this three carbon compound. hence is called as C3 pathway. hence C3 plants.
Answer:
in male lion, two methyl groups are present in its structure while in female lion, two hydroxl groups are present in its structure
Explanation:
The chemical structure of the carbon atom is different in both male and female lion because both male and female lions have different sex harmones which are totally different from one another. In male lion, testosterone is a sex hormone whose chemical formula is C19H28O2 and two methyl groups and one hydroxl group are present in its structure while in female lion, oestradiol is a sex hormone having a chemical formula C18H24O2 and two hydroxyl groups are present.
C.
The blood fluid contains less water, which will cause the water to go into the cells and make them swell up.
Answer:
D. 1 BB : 2 Bb : 1 bb
Explanation:
This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.
If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:
Bb = B and b
Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:
1 BB : 2 Bb : 1 bb
BB and Bb = black fur guinea pigs
bb = white fur guinea pigs
