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Svetllana [295]
2 years ago
9

3.14 LAB: Input and formatted output: Caffeine levels A half-life is the amount of time it takes for a substance or entity to fa

ll to half its original value. Caffeine has a half-life of about 6 hours in humans. Given caffeine amount (in mg) as input, output the caffeine level after 6, 12, and 24 hours. Use a string formatting expression with conversion specifiers to output the caffeine amount as floating-point numbers.
Computers and Technology
1 answer:
nata0808 [166]2 years ago
8 0

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

double caffeineMg;

cin>>caffeineMg;

cout<<"After 6 hours: "<<fixed<<setprecision(2)<<caffeineMg/2.0<<" mg\n";

cout<<"After 12 hours: "<<fixed<<setprecision(2)<<caffeineMg/4.0<<" mg\n";

cout<<"After 24 hours: "<<fixed<<setprecision(2)<<caffeineMg/8.0<<" mg\n";

return 0;

}

Explanation:

  • Declare a variable for caffeine and take the input from user.  
  • Print the results by dividing the caffeine by relevant Half Life.
  • Use setprecision function to display the result up to 2 decimal places.
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enyata [817]

Correct question.

Which role is delegated to personnel of the IT department and how is responsible for maintaining the integrity and security of the data?

Answer:

<u>data custodian</u>

<u>Explanation:</u>

Remember, every organization generates data, and large organizations generate even larger data.

Hence, the role of a data custodian in an organization requires He implements measures to protect the organization's data, store and backup the data, as well as granting access to the data to authorized persons when needed.

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2 years ago
Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a semicolon (no s
Pavlova-9 [17]

Answer:

Replace /* Your code goes here */  with

for(i =0; i<NUM_VALS; i++) {

    printf("%d", origList[i]*offsetAmount[i]);

printf(";");

}

Explanation:

The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount

for(i =0; i<NUM_VALS; i++) {

This line calculates and print the product of element in origList and its corresponding element in offsetAmount

    printf("%d", origList[i]*offsetAmount[i]);

This line prints a semicolon after the product has been calculated and printed

printf(";");

Iteration ends here

}

5 0
2 years ago
Write a function string middle(string str) that returns a string containing the middle character in str if the length of str is
Katen [24]

Answer:

function getMiddle(s) {

return s.length % 2 ? s.substr(s.length / 2, 1) : s.substr((s.length / 2) - 1, 2);

}

// I/O stuff

document.getElementById("submit").addEventListener("click", function() {

input = document.getElementById("input").value;

document.getElementById("output").innerHTML = getMiddle(input);

});

Explanation:

// >>> is an unsigned right shift bitwise operator. It's equivalent to division by 2, with truncation, as long as the length of the string does not exceed the size of an integer in Javascript.

// About the ~ operator, let's rather start with the expression n & 1. This will tell you whether an integer n is odd (it's similar to a logical and, but comparing all of the bits of two numbers). The expression returns 1 if an integer is odd. It returns 0 if an integer is even.

// If n & 1 is even, the expression returns 0.

// If n & 1 is odd, the expression returns 1.

// ~n & 1 inverts those two results, providing 0 if the length of the string is odd, and 1 if the length of the sting is even. The ~ operator inverts all of the bits in an integer, so 0 would become -1, 1 would become -2, and so on (the leading bit is always the sign).

// Then you add one, and you get 0+1 (1) characters if the length of the string is odd, or 1+1 (2) characters if the length of the string is even.

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2 years ago
If the computer has an encrypted drive, a ____ acquisition is done if the password or passphrase is available. a. passive b. sta
Aleonysh [2.5K]

Answer: C. Live

Explanation:

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7 0
2 years ago
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ella [17]
The question involves basic polymorphism. The following is the partial flow of the program.

baseItemPtr = new BaseItem();
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itemList.add(baseItemPtr);
itemList.add(derivedItemPtr);

for (i = 0; i < itemList.size(); ++i) {
itemList.get(i).printItem();
}

return;
7 0
2 years ago
Read 2 more answers
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