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Marina86 [1]
2 years ago
13

In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation dur

ing its current time quantum? The process will terminate itself. The process will be terminated by the operating system. The process's state will be changed from running to blocked. None of the mentioned.
Computers and Technology
1 answer:
masha68 [24]2 years ago
7 0

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

You might be interested in
7. Test Average and Grade Write a program that asks the user to enter five test scores. The program should display a letter grad
Alenkasestr [34]

Answer:

The code solution is written in Java.

  1. import java.util.Scanner;
  2. public class TestScore {
  3.    public static void main(String[] args) {
  4.        Scanner input = new Scanner(System.in);
  5.        System.out.print("Please enter first score: ");
  6.        double firstScore = input.nextDouble();
  7.        System.out.println("Grade: " + determineGrade(firstScore));
  8.        System.out.print("Please enter second score: ");
  9.        double secondScore = input.nextDouble();
  10.        System.out.println("Grade: " + determineGrade(secondScore));
  11.        System.out.print("Please enter third score: ");
  12.        double thirdScore = input.nextDouble();
  13.        System.out.println("Grade: " + determineGrade(thirdScore));
  14.        System.out.print("Please enter fourth score: ");
  15.        double fourthScore = input.nextDouble();
  16.        System.out.println("Grade: " + determineGrade(fourthScore));
  17.        System.out.print("Please enter fifth score: ");
  18.        double fifthScore = input.nextDouble();
  19.        System.out.println("Grade: " + determineGrade(fifthScore));
  20.        System.out.println("Average score: " + calcAverage(firstScore, secondScore, thirdScore, fourthScore, fifthScore));
  21.    }
  22.    public static double calcAverage(double score1, double score2, double score3, double score4, double score5){
  23.        double average = (score1 + score2 + score3 + score4 + score5) / 5;
  24.        return average;
  25.    }
  26.    public static String determineGrade(double score){
  27.        if(score >= 90){
  28.            return "A";
  29.        }
  30.        else if(score >= 80 ){
  31.            return "B";
  32.        }
  33.        else if(score >=70){
  34.            return "C";
  35.        }
  36.        else if(score >=60){
  37.            return "D";
  38.        }
  39.        else{
  40.            return "F";
  41.        }
  42.    }
  43. }

Explanation:

Firstly, create the method, <em>calcAverage()</em>, that takes five test scores. Within the method, calculate the average and return it as output. (Line 33 - 36)

Next, create another method, <em>determineGrade()</em>, which takes only one score and return the grade based on the range of the  score. (Line 38 -54)

Once the two required methods are created, we are ready to prompt use for input five test scores using Java Scanner class. To use get user input, create a Scanner object (Line 7). Next, use getDouble() method to get an input score and assign it to variables firstScore, secondScore, thirdScore, fourthScore & fifthScore, respectively. Once a score input by user, call determineGrade() method by passing the input score as argument and immediately print out the return grade. (Line  9 - 27)

At last, call calcAverage() method by passing the first test score variables as argument and print out the returned average value. (Line 29).

5 0
2 years ago
I think you have been doing a great job but you haven’t been signing many people up for our new service feature I want you to se
STatiana [176]

Answer:

24 customers

Explanation:

Given

Customers = 96

p = 25\% --- proportion to sign up

Required

The number of customers to sign up

This is calculated as:

n = p * Customers

So, we have:

n = 25\% * 96

n = 24

5 0
2 years ago
The ratio of Chris an iood Dom's ages is
irinina [24]

Answer:

28 years

Explanation:

Let's represent present age of Chris and Dom as C and D respectively. Then since ratio of present age of Chris and Dom is 3:4. Therefore,

\frac{C}{D}=\frac{3}{4}

C=\frac{3}{4}D   ...(1)

Now, it is given that in 7 years their age ratio will become 4:5. Therefore,

\frac{C+7}{D+7}=\frac{4}{5}

5C+35=4D+28\\

Using value of C from equation(1),

5\times\frac{3}{4}D-4D=28-35

15D-16D=-28\\-D=-28\\ D=28

Thus, present age of Dom is 28 years.

8 0
2 years ago
The it department is reporting that a company web server is receiving an abnormally high number of web page requests from differ
Talja [164]
<span>In the scenario in which the IT department is reporting that a company web server is receiving an abnormally high number of web page requests from different locations simultaneously the DDoS security attack is occurring.
</span>DDos stands for Distributed Denial of Service<span> . This </span><span>attack is an attempt to make an online service unavailable by overwhelming it with traffic from multiple sources.</span>
8 0
2 years ago
Using the college registration example from section 6.7.3 as a starting point, do the following:
Arada [10]

Answer:

Explanation:

NCLUDE Irvine32.inc

TRUE = 1

FALSE = 0

.data

gradeAverage WORD ?

credits WORD ?

oKToRegister BYTE ?

str1 BYTE "Error: Credits must be between 1 and 30" , 0dh,0ah,0

main PROC

call CheckRegs

exit

main ENDP

CheckRegs PROC

push edx

mov OkToRegister,FALSE

; Check credits for valid range 1-30

cmp credits,1 ; credits < 1?

jb E1

cmp credits,30 ; credits > 30?

ja E1

jmp L1 ; credits are ok

; Display error message: credits out of range

E1:

mov edx,OFFSET str1

call WriteString

jmp L4

L1:

cmp gradeAverage,350 ; if gradeAverage > 350

jna L2

mov OkToRegister,TRUE ; OkToRegister = TRUE

jmp L4

L2:

cmp gradeAverage,250 ; elseif gradeAverage > 250

jna L3

cmp credits,16 ; && credits <= 16

jnbe L3

mov OkToRegister,TRUE ; OKToRegister = TRUE

jmp L4

L3:

cmp credits,12 ; elseif credits <= 12

ja L4

mov OkToRegister,TRUE ; OKToRegister = TRUE

L4:

pop edx ; endif

ret

CheckRegs ENDP

END main

8 0
2 years ago
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