Answer:
import csv
def Csvreader(filename):
with open("filename", "r") as file:
content = file.csv_reader()
list_content = list(content)
file.close
return list_content
Explanation:
This is a python description of the function that reads the csv file and converts it to a list, from the list, each item can accessed with its index and updated directly. Use this to draw the same conclusion for a java program.
Answer:
The advantage for the above condition is as follows:-
Explanation:
- If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
- It is because when there is a needs to change the value of that variable, then it can be done when the user changes the value in one place. There is no needs to change the vale in multiple places.
- But if there is a value in multiple places instead of a variable and there is no constant variable, then the user needs to change the value in multiple places.
Answer:
boolean recalled;
((modelYear>=1995 && modelYear <=1998) || (modelYear>=2004 && modelYear<=2006)) ? recalled =true : recalled =false;
Explanation:
In the first line of the code we declare the variable of type boolean (values can only be true or false) then using the conditional expression operator (ternary operator) in place of an if statement, We state the conditions of the years that will return true and vice versa
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Answer: c. Depending on context the same sequence of bits may represent different types of information.
Explanation:
The options for the question are:
A. Computing devices use patterns of bits to represent complex information
B. Abstraction helps represent complex information by surfacing complexity that might otherwise be hidden
C. Depending on context the same sequence of bits may represent different types of information
D. Common abstractions that are represented by computing devices include numbers, characters, and color.
The following are true of how computers represent complex information:
• Computing devices use patterns of bits to represent complex information
• helps represent complex information by surfacing complexity that might otherwise be hidden
• Common abstractions that are represented by computing devices include numbers, characters, and color.
Therefore, the option that is not true of how computers represent complex information is that "depending on context the same sequence of bits may represent different types of information".
