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____ [38]
2 years ago
9

Write a class called Counter that represents a simple tally counter, which might be used to count people as they enter a room. T

he Counter class should contain a single integer as instance data, representing the count. Write a constructor to initialize the count to zero. Write a method called click that increments the count and another method called get Count that returns the current count. Include a method called reset that resets the counter to zero. Finally, create a driver class called CounterTest that creates two Counter objects and tests their methods.
Computers and Technology
1 answer:
Sonja [21]2 years ago
4 0

Answer:

Code is in java

Explanation:

Code is self explanatory, added come comments to explain more about the code.

public class CounterDriver {

   public static void main(String[] args){

       // Creating counter first object

       Counter counter1 = new Counter();

       //performing 2 clicks

       counter1.click();

       counter1.click();

       // displaying counter 1 click count

       System.out.println("Total Number of counter1 clicks :"+counter1.getCount());

       // resetting counter 1 click count

       counter1.reset();

       // again displaying click count which will be 0 after reset

       System.out.println("Total Number of counter1 clicks :"+counter1.getCount());

      // Same operation goes with counter 2  

       // the only difference is that it performs 3 clicks

       Counter counter2 = new Counter();

       counter2.click();

       counter2.click();

       counter2.click();

       System.out.println("Total Number of counter2 clicks :"+counter2.getCount());

       counter2.reset();

       System.out.println("Total Number of counter2 clicks :"+counter2.getCount());

   }

}

class Counter{

   int count;

// defining constructor which will initialize count variable to 0

   public Counter(){

       this.count=0;

   }

// adding click method to increment count whenever it's called

   public void click(){

       this.count++;

   }

// getCount method will return total count

   public int getCount(){

       return this.count;

   }

// reset method will set count to 0

   public void reset(){

       this.count = 0;

   }

}

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Explanation:

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Write a sequence of statements that create a file named "greeting" and write a single line consisting of "Hello, World!" to that
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Answer:

The solution code is written in Python 3 as below:

  1. outfile = open("greeting.txt", "w")
  2. outfile.write("Hello World")
  3. outfile.close()

Explanation:

To create a simple text file in Python, we can use Python built-in function, <em>open()</em>. There are two parameters needed for the open() function,

  1. the file name and
  2. a single keyword "w". "w" denote "write". This keyword will tell our program to create a file if the file doesn't exist.

The statement <em>open("greeting.txt", "w")</em> will create a text file named "<em>greeting.txt</em>" (Line 1)

To fill up the content in the greeting.txt, we use <em>write()</em> method. Just include the content string as the argument of the <em>write()</em> method. (Line 2)

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Create a single list that contains the following collection of data in the order provided:
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Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

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A bunch of computer scientists take over an island and start their own country. They want the license plates to use binary numbe
Thepotemich [5.8K]

Answer:

  • <em>Their country can support </em><u><em>   128   </em></u><em>unique license plates</em>

Explanation:

Since there is space for<em> 7 digits </em>on each <em>license plate</em>, the first plate starts at <em>0000000 </em>(seven 0).

<em>Binary numbers</em> contain only the digits 0 and 1.

Thus, there are only two possibilities for each digit.

Using the multiplication counting principle, the number of total different binary numbers, with seven digits is 2 multiplied seven times:

  • 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2⁷ = 128 ← answer
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