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lilavasa [31]
2 years ago
6

An Airplane travels about 1500km in a straight line between Toronto and Winnipeg . However, the plane must climb to 10 000 m dur

ing the first 200km. Then it must descend 10 000 m during the final 300km
1. How much Distance do the climb and desent add to the flight? ...?
Mathematics
2 answers:
Lena [83]2 years ago
5 0
Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:<span>200 * Sec <span>[<span>ArcTan <span>[10/200]</span></span>]</span> = 10</span>√ 401 km
and the decent distance is:<span>300 * Sec <span>[<span>ArcTan <span>[<span>10/300</span>]</span></span>]</span> = 10</span>√901 km
So add the given results above with 500 km and this will be the additional distance that <span>plane moves through the air.
The answer would be in the unit meters.
</span><span>(<span>(10</span></span>√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
DedPeter [7]2 years ago
4 0

Answer:

Climbing and descending add to the flight 416 m

Step-by-step explanation:

The plane must climb to 10 km during the first 200 km. This forms a right triangle, where 10 and 200 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:

√(10² + 200²)

The plane must descend 10 km during the final 300km. This forms a right triangle, where 10 and 300 are its legs and the hypotenuse is the distance travelled by the airplane. From Pythagorean theorem, that distance is:

√(10² + 300²)

If the airplane climbed during 300 km and descended during 200 km, then during 1500 - 200 - 300 = 1000 km it doesn't climb or descend.

The distance added by climbing and descending is:

1000 + √(10² + 200²) + √(10² + 300²) - 1500 = 0.416 km or 416 m

Guest
1 year ago
Why do you take away 1500 I final formula though.
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