Suppose you roll a six-sided 50 times and calculate the mean roll, x .
1 answer:
Answer:
0.07
a. the distribution will be a normal distribution.
c. we would suspicious ins there is a 2 % chance of getting the required value.
Step-by-step explanation:
Let the number of times, t be = 50
Assuming that the die is fair
standard deviation = 1.71
mean = 3.5
suppose we want tp find the probability of a 2 showing. The solution becomes:
probability =
c. the mean of rolls will be 0.07
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The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.