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Lubov Fominskaja [6]
2 years ago
12

John works for Internal Computer Specialists, which focuses on helping small business owners resolve MIS infrastructure issues.

John's tasks include cleaning and replacing motherboards, cables, and internal components such as DVDs and hard drives. What does John's role at Internal Computer Specialists focus on fixing?
Computers and Technology
1 answer:
lisov135 [29]2 years ago
6 0

Answer:

Hardware.

Explanation:

All electronics devices like computer servers, DVDs, smartphones and cell phones, wrist watches etc, comes with two main components, they are hardware and software.

The hardware components are the physical part of the device, while the software component is the written instructions configured to the hardware for executing tasks.

Cleaning the motherboard in a computer system, fixing a DVD, servicing other internal components of devices are all hardware maintenance and repair services.

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John works for Internal Computer Specialists, which focuses on helping small business owners resolve MIS infrastructure issues.
lisov135 [29]

Answer:

Hardware.

Explanation:

All electronics devices like computer servers, DVDs, smartphones and cell phones, wrist watches etc, comes with two main components, they are hardware and software.

The hardware components are the physical part of the device, while the software component is the written instructions configured to the hardware for executing tasks.

Cleaning the motherboard in a computer system, fixing a DVD, servicing other internal components of devices are all hardware maintenance and repair services.

6 0
2 years ago
Five routers are to be connected in a point-to-point subnet. between each pair of routers, the designers may put a high-speed li
Natalija [7]

Let assume are lettered A to E in that order. Thus, there will be 10 potential lines: AB, AC, AD, AE, BC, BD, BE, CD, CE and DE. Each of these potential lines has 4 possibilities. Therefore, the total number of topologies is 4¹⁰=1,048,576. 1,048,576. At 100ms <span>it will take 104,857.6 seconds which is slightly above 29 hours to inspect each and one of them.</span>











6 0
2 years ago
Suppose a computer has 16-bit instructions. The instruction set consists of 32 different operations. All instructions have an op
Kazeer [188]

Answer:

2^7= 128

Explanation:

An instruction format characterizes the diverse part of a guidance. The fundamental segments of an instruction are opcode and operands. Here are the various terms identified with guidance design:  Instruction set size tells the absolute number of guidelines characterized in the processor.  Opcode size is the quantity of bits involved by the opcode which is determined by taking log of guidance set size.  Operand size is the quantity of bits involved by the operand.  Guidance size is determined as total of bits involved by opcode and operands.

6 0
2 years ago
You are an ISP. For the Address Block 195.200.0.0/16 a. If you have 320 Customers that need 128 addresses/customer - will there
12345 [234]

Answer:

a. The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.

b. 195.200.0.0/22

Explanation:

195.200.0.0/16

The number of bits to give 512 is 9

2^9=512

2^8=256 which is not up to our expected 320 customers that requires a network ip

Note we have to use a bit number that is equal or higher than our required number of networks.

The number of host per each subnet of the network (195.200.0.0/25) is (2^7)-2= 128-2=126

The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.

b. 64 customers requires  6 bits to be taken from the host bit to the network bit

i.e 2^6 = 64

195.200.0.0/22

The number of host per each subnet of the network (195.200.0.0/22) is (2^10)-2=1024 - 2 = 1022 hosts per subnet

This network meet the requirement " 64 customers want 128 addresses/customer "

5 0
2 years ago
Write a while loop that prints user_num divided by 2 until user_num is less than 1. The value of user_num changes inside of the
WITCHER [35]

Answer:

The code to this question can be defined as follows:

Code:

#include <stdio.h> //defining header file

int main() //defining main method

{

float user_num; //defining float variable

printf("Enter a value: "); //message

scanf("%f",&user_num); //input value from user end

printf("%f, ",user_num); //print value

while (user_num>1) //loop to calculte value

{

user_num=user_num/2; //diving value

printf("%f, ",user_num); //print value.

}

   return 0;

}

Output:

Enter a value: 20

20.000000, 10.000000, 5.000000, 2.500000, 1.250000, 0.625000,  

Explanation:

Description of the code as follows:

  • First, a float variable "user_num" is declared, in which we take input from the user-end.
  • In the next step, a while loop is declared, that uses the above variable to calculates its value.
  • Inside the loop variable "user_num" divide its value by 2 and holds its calculated value, to print its value the "printf" method is used that prints its value.  
8 0
2 years ago
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