A single genetic locus that controls more than one trait is said to be pleiotropic
Answer:
The scaling exponent will be 0.75
Explanation:
According to a famous article by Max Kleiber*, the scaling of the metabolic rate or energy consumption for mammals Pmetab (measured in kcal/day) with the body mass Mb (measured in kilograms) is P metab = 70 Mb^0.75 .
What is the scaling exponent (the quantity x in a scaling law A = cMbx) for the specific metabolic rate as a function of the animal’s body mass?
he scaling of the metabolic rate or energy consumption for mammals P=kcal/day
Mb=body mass in kilograms
Comparing
P metab = 70 Mb^0.75 .
with A = cMb^x
the scaling exponent will be 0.75
metabolic rate is the energy(in kilojoule) consumed at rest. it accounts for the highest amount of energy a body consumes daily
Answer: herbivore, eukaryote, primary consumer
Explanation:
The red squirrel can be described by the following features.
1. Herbivore: A herbivore is an animal which is dependent upon the plant and their products for it's food requirement. Here, the red squirrel is the herbivore because it is dependent upon the spruce tree seeds for their food requirement.
2. Eukaryote: A eukaryotic organism is the one which has well define nucleus and encloses the genetic material in the nucleus. The red squirrel is a complex eukaryotic organism.
3. Primary consumer: In a food chain a primary consumer is an organism which is dependent upon plants and their food products for energy and food needs. The red squirrel is the primary consumer this is because of the fact that it consumes on the seeds of the spruce trees.
So naturally, Water loves to be with water. This is just a common knowledge of biology. The side with the least amount of water will recognize that the opposing side has more water. Water molecules in Side A will essentially try and cross the selectively permeable membrane and go onto the crowded side. This will make the Cell in A become lysed and it will shrink. Your answer will be:
C. The Water level will increase on side B and decrease on Side A until concentrations are equalized.
I guess the point about increasing level of oxygen is most correct......
