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2 years ago

You find your dependent variable has a high degree of kurtosis. What is the first way to try to fix it?

1 answer:

7 0

The first way to try to fix this is to apply logarithm to the observations on the dependent variable. This is going to make the dependent variable with high degree of kurtosis normal.

Note that sometimes, the resulting values of the variable will be negative. Do not worry about this, as it is not a problem. It does not affect the regression coefficients, it only affects the regression intercept, which after transformation, will be of no interest.

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Find the unit price of 60lbs of honey for $123.99. Round your answer to the nearest cent if necessary.

astraxan [27]

The unit price is $2.07 per lb (pound).

6 0

2 years ago

Read 2 more answers

Jennifer has a square bedroom. The area of her room is 144 ft2. What is the length of one side of Jennifer’s room?

Jobisdone [24]

Answer:

Option B. $12\ ft$

Step-by-step explanation:

we know that

The area of a square is equal to

$A=x^{2}$

where

x is the length side of the square

In this problem we have

$A=144\ ft^{2}$

substitute and solve for x

$144=x^{2}$

suqre root both sides

$x=12\ ft$

7 0

2 years ago

Which of the following options have the same value as 60\%60%60, percent of 949494?

garri49 [273]

<h2>Answer:</h2>

The correct options are:

Choice A

Choice C

and Choice E

<h2>Step-by-step explanation:</h2>

We are asked to find the value of:

60% of 94

We know that: it is represented as:

$60\%\ of\ 94=\dfrac{60}{100}\times 94\\\\\\=0.6\times 94$

Choice A)

$0.06\cdot 940$

We know that:

$0.6\times 94$ could also be written as:

$0.06\times 940$

Since we multiplied and divide by 10 such that:

$=0.6\times 94\times \dfrac{10}{10}\\\\\\=\dfrac{0.6}{10}\times (94\times 10)\\\\\\=0.06\times 940$

Hence, option: A is correct.

Choice B)

$0.6\cdot 940$

This option is incorrect.

Since by choice A we get that the correct expression is: $0.06\cdot 940$

Choice C)

We get:

$\dfrac{3}{5}\cdot 94$

This option is correct.

Since,

$60\%\ of 94\ is:\\\\\\=\dfrac{60}{100}\cdot 94\\\\\\=\dfrac{3}{5}\cdot 94$

Choice D)

$60\cdot 94$

This option is incorrect because the actual expression is:

$0.6\cdot 94$

Choice E)

[/tex]\dfrac{60}{100}\cdot 94[tex]

This is the correct expression.

5 0

2 years ago

Read 2 more answers

NEED HELP ON NUMBER 13 AND 14

Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds is given by the solution of the equation

$8=y^4 +2y^3 - 4y^2 -5y +14.$

We graph this equation and find the solutions to be

$y=1;$ $y=1.302;$ $y=-2;$ $y=-2.302.$

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when $p(t)$

$t^3 -14t^2 +20t +120$

We graph this inequality and find the solutions to be

$t$ and $4.88$

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years $4.88$

5 0

2 years ago

Felecia left her home to visit her daughter, driving 45mph. Her husband waited for the dog sitter to arrive and left home 20 min

Jet001 [13]

Felecia's husband will catch up to her 1 hour 30 minutes after leaving.

Step-by-step explanation:

Step 1; Felecia is traveling at 45 mph, her husband starts 20 minutes after her but travels at a speed of 55 mph. So first we need to calculate how much of a head start Felecia got.

Head start = $\frac{1}{3}$ × 45 miles an hour = 15 miles.

So Felecia got a head start of 15 miles.

Step 2; Since Felecia and her husband are traveling at different rates, we can determine how much distance there is between them. Since Felecia is traveling at 45 mph and her husband is traveling at 55 mph, their gap in between is closing at a rate of 55 - 45 = 10 miles every hour. So for every hour, the gap between them is closing by 10 miles.

Total gap initially = 15 miles.

The rate at which gap is being closed = 10 miles an hour.

Time to close the gap = 15 / 10 = 1.5 hours.

8 0

2 years ago