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Lelu [443]
2 years ago
6

Imagine that a brilliant but quirky scientist in the biology department manages to put you in a deep freeze and

Biology
1 answer:
serious [3.7K]2 years ago
5 0

Answer: the answer is A!

Explanation:

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What is formed when reverse transcriptase is used on a strand of mRNA?
posledela
A strand of DNA 
DNA is used to find the mRNA, so the mRNA can be used to find a strand of DNA.
6 0
2 years ago
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There are six people in the Fisher family. Olivia and Marcus are the parents. They have four children: Violet, Nathan, Jonas, an
Trava [24]
<span> Wow, this is a big question, but here goes. Freckles q: 1) Since freckles is the dominant phenotype, this means that Olivia must have the recessive phenotype, which is only given by the genotype ff. FF and Ff would both give freckles because, again, freckles is dominant. So any genotype with F_ would give freckles. 2)Same answer as #1. 3) Since they only have f alleles to pass on, both the dad and the mom will pass on one f each to 100% of their children. So all will have genotype ff and no freckles.
Hairline q: Since the parents are heterozygous, this means that their genotype has one of each allele to give Hh. (Even though you said they are quadruplets, I'm going to assume they are fraternal (different DNA) b/c otherwise they'd always have the same genotype if they are identical). 1) Okay, so when you do the Punnett square for Hh x Hh, you'll get 1HH:2Hh:1hh. Since widow's peak is dominant, any genotype with H_ gives the widow's peak. So, there are 3 options from the Punnett square, so you'll have 3 of the kids with widow's peak. Theres a 3/4 chance that a child will have widow's peak from these parents. 2) Since straight hairline is recessive, you need hh to get this phenotype and there is only one option. So, there will only be one child with the straight hairline. (1/4 chance). 3) Homozygous dominant means that you have two of the dominant allele, so HH. Since there is only 1 option, there is only one child with this genotype.
Tongue q: Since rolling the tongue is a dominant trait and the parents both can't roll their tongues, they must have a homozygous recessive genotype for this to happen (remember in dominance, any genotype with a dominant allele will give the dominant phenotype), so they have tt. 1) Since again they can only pass on t alleles, the kids will all have tt, so no one can roll their tongues. 2) None of them are hybrids because there was no variety in the genotypes or anything. Both parents had tt, so they were same in genotype. 3) She will have tt because of the above stated reasons.
Dimples q: Since all four kids have dimples, the dominant phenotype, they must all have the genotype D_ (either Dd or DD). 1) Since Marcus is a hybrid, this means that he had parents that were DD x dd to give him the genotype Dd. Since he has a recessive allele d in his genotype, Olivia must have all dominant alleles to make sure that each child has at least one dominant D. So, she must have the genotype DD. 2) Since she is DD, the dominant alleles will make her have dimples.
Earlobe q: 1) Since the parents are EE both, a cross of EE x EE will give EE genotype children. So, all children have EE, this means they all have free earlobes. So the ratio is 100% free to 0% attached earlobes. 2)Homozygous means they have two of the same alleles. Since all of them have EE, 100% of them are homozygous.
PTC q: Marcus has genotype bb and Olivia has genotype Bb because she is heterozygous. 1) The cross of bb x Bb gives 1Bb:1bb, So, 1/2 can taste the paper, so 50% can taste. 2) Since Violet can't taste the paper, she must be recessive and have the genotype bb. Since both of the boys can taste, they must have the genotypes Bb. Since 1/2 is already Bb, Claudia must be bb to help create the 50% that can't taste in the kids. 3)So, 2 people out of the family can taste the paper. Even though Olivia has Bb and should be able to taste, she can't. So, only Jonas and Nathan can taste the paper.
Pheww... done.. Hope this helps! :)<span>
</span></span>
7 0
2 years ago
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What would happen to life on earth if the rates of photosynthesis and cellular respiration in all phototrophs were equal?
Reptile [31]

Answer:

When the level of release of carbon dioxide during respiration and use of carbon dioxide during photosynthesis this results in a compensation point. At compensation point the net available carbon dioxide to phototrophs becomes  zero. As, carbon dioxide is the chief ingredient for photosynthetic products like glucose and oxygen. These products are used up during the process of respiration. When the rates of two processes photosynthesis and respiration becomes equal. Phototrophic organisms will not be able to compensate for lack of carbon dioxide levels. Phototrophs will not be able to produce their food in the form of glucose and hence will not be able to respire too. This will result in lack of overall available food from phototrophs and lack of available oxygen for respiration. This will result in decline of organisms on earth.

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2 years ago
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7. Mrs. Everhart developed the theory that all bulldogs are great pets. After all her bulldog Meatball is a
Leno4ka [110]

Answer:

No it is not a scientific theory.

Explanation:

An explanation of any aspect of the natural phenomenon of the world that can be tested several times and well supported by the evidence, and follows the scientific method. Furthermore known as scientific theory.

Presently, a logical hypothesis must meet a few rules, and one of those is that it must be upheld by a few (and free) strands of proof.  

For this situation, we have just one hypothesis, that bulldogs are great pet and Meatball is great among bulldogs, and it isn't sufficient, at that point it can not be a scientific theory.

8 0
2 years ago
The zebra population is exploding in the savannah. At the same time, populations of many small animals that live in the Red Gras
Darya [45]
This would be because the grass that they eat are in the area that the zebra population is booming in.
3 0
2 years ago
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