Answer:
Methemoglobinemia
Explanation:
Methemoglobinemia (also known as the blue baby syndrome), is a condition with multiple etiologies which is associated with the lack of oxygen in the blood. This syndrome affects the function of red blood cells by altering the amount of hemoglobin protein, which carries and distributes oxygen to the body. Methemoglobinemia may be acquired by exposure to drugs and/or toxins. In this regard, it has been shown that high levels of nitrates in the water may induce this syndrome in infants.
Answer:
There will be few if any complications.
Explanation:
Just took the unit test review
Answer:
The correct option is D. The average mass of plants exposed to 3 g of herbicide was 10g.
Explanation:
As the vertical axis is labelled as average plant mass, it will make the y- coordinate.
As the horizontal axis is labelled as Herbicide (g/plant), it will make the x-axis.
The coordinates for the given value are (3,10). 3 will be the value of the x- coordinate. Hence, it will show the average mass of the plant at the plotted point which will be 3 g.
10 will show the value of the y- coordinate which will be the amount of herbicide given to the plant.
Hence, Dis the correct option.
The answer to the first unknown in the problem is the "Areolar" while in the second unknown in the problem is the "Cartilage". Hence, to complete the given statement in the problem, we have an example of a high vascular tissue is "AREOLAR" tissue and as an example also of a tissue that is not highly vascular is the "CARTILAGE".
Answer: if i want to breed a rose and i don't have a certain kind of rose, i have to cross between them until i have a kind of rose that express the phenotype i was looking for. Once i've got it, i'll try to cross it with another rose and generate more species like that to cross with the rose that express the phenotype, this favors to generate a specie that have a pure phenotype.
Explanation: The answer is explain by the Mendel's laws.
Mendel's second law:
if you have two roses that are heterozygous and you cross them, their offspring have a 25% probability of generating a homozygous phenotype for a certain recessive characteristic (such as the rich smell of roses that is not a dominant character), 50% of generate heterozygotes with a dominant phenotype, and 25% generate other homozygotes with a dominant phenotype.
Once the offspring with the recessive homozygous character are obtained, it is possible to start making crosses between those of a recessive nature and there Mendel's first law applies
All the homozygous recessive individuals that are crossed will have a 100% homozygous recessive offspring.
Also, if you cross heterozygotes with another heterozygotes the offspring will be 100% heterozygotes