If we assume Aa is husband which is hetero-zygote and aa is wife which is normal then their cross will be Aa X aa and first generation will be Aa aa aa Aa.
Further explanation
Cross between Aa (heterozygote male) and aa (normal female)
Here is cross between a normal wife (aa) and a heterozygote husband (Aa)
Aa X aa
First generation
Aa Aa aa aa
Result
It is clearly seen that ration is 1:1 which mean half are heterozygote and half are normal offspring. As they already told about number of offspring which is 25, So according to 1:1 12.5 are normal and 12.5 are heterozygote.
Chi-square Test
It is test used to evaluate the observed the expected values.
Chi-square formula
χ2=∑(o-e)2/e
Here o= observed and e= expected
Calculation through chi-square value
It is given below
For heterozigous (14-12.5)2/12.5=0.18
For normal (11-12.5)2/12.5=0.18
By putting values of both heterozygous and recessive in chi-square formula
χ2=0.18+0.18=0.36
Answer details
Subject: Biology
Level: High school
Key words
- Cross between Aa (hetrozygote male) and aa (normal female)
- Chi-square Test
- Chi-square formula
- Calculation through chi-square value
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From the differences in the width of the alternating stripes, we can conclude that the lengths of time represented by this evidence varies.
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Mitochondria and the chloroplast
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In both mitochondria and chloroplast,have these mechanisms for the production of ATP .
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