Answer:
d. The phosphate group added to ADP to make ATP comes from free inorganic phosphate ions.
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding
The cow is demonstrating disruptive selection by only choosing to eat white flowers.
Answer:
Conjugation.
Explanation:
I just took the test on Edge 2020. Hope this helps! Good luck!
