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Luda [366]
2 years ago
11

A scientist was observing a population of sea cucumbers in coastal waters. Over a 10-day period, she collected the following inf

ormation about the distribution of the individuals within a 10-meter square plot:
Distribution of Sea Cucumbers within a 10-Meter Square Plot

Time of Day

Average Distance between Individuals (cm)

Midnight

7.0

4 a.m.

7.8

8 a.m.

43.7

Noon

172.0

4 p.m.

349.5

8 p.m.

58.9

Midnight

7.0


Use the data above as a basis as you answer the following questions: (10 points)

(a) Identify THREE biotic or abiotic factors that could cause the sea cucumbers to vary their distance from each other throughout the day.

(b) Using one of the factors listed in part (a) as an independent variable, write a hypothesis that proposes how this variable could cause the sea cucumbers to vary their distance from each other.

(c) Design a procedure for a controlled experiment to test your hypothesis.

(d) Describe the results that would support your proposed hypothesis and the results that would refute your hypothesis.
Biology
1 answer:
victus00 [196]2 years ago
5 0
I think the answer is A im sorry if its not right 
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The answer is they produce endospores.

Explanation:

The endospores are dormant, non-reproductive, tough bacterial spores that ensure the survival of bacteria in adverse conditions.

During the environmental stress, such as starvation, desiccation, radiation and chemical treatment many bacteria form dormant endospores. These endospores germinate again when the conditions become favorable.

Hence, if drought conditions lead the stream to dry up, the bacteria that live there would produce endospores to survive.

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What would be the consequence to an organism if they are missing the following DNA repair mechanisms:
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Answer:

a. DNA polymerase proofreading:   consequence of its absence is the DNA mutation

b.  Mismatch repair enzymes : consequence of its absence impedes homologous recombination resulting in the final mutation

c. Nucleotide excision repair enzymes : the absence of nucleotide cleavage repair enzymes would impede the functioning of damaged DNA repair mechanisms

Explanation:

a. DNA polymerases are the enzymes that form the DNA in cells. During DNA replication (copying), most DNA polymerases can "check their work" with each base they add. This process is called review. If the polymerase detects that you have added a wrong nucleotide (incorrectly paired), remove it and replace it immediately, before continuing with DNA synthesis

b. In homologous recombination, the information from the homologous chromosome that matches that of the damaged one (or from a sister chromatid if the DNA has been copied) is used to repair the fragmentation. In this process the two homologous chromosomes are approached and the undamaged region of the homologue or the chromatide is used as a template to replace the damaged region of the broken chromosome. Homologous recombination is "cleaner" than the union of non-homologous ends and does not usually cause 11 mutations

c. Excision repair: damage to one or a few DNA bases is usually fixed by removing (excising) and replacing the damaged region. In repair by base cleavage, only the damaged base is removed. In nucleotide excision repair, as in the mating repair we saw earlier, a nucleotide section is removed

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The name of the bacterium is derived from its function or the metabolic ability as it performs denitrification on thio (sulfur) based inorganic compounds by the process of oxidation. This process helps in bioremediate groundwater by these processes of nitrogen fixation by oxidation of inorganic compounds of sulfur.

Thus, the correct answer is - nitrification, denitrification, nitrogen fixation, and decomposition.

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