So let’s substitute that into the
third equation and solve for B. B = H + T B = 9 + (9 + 1/2B) B = 18 + 1/2B Then
subtract 1/2B from both sides: 1/2B = 18 Multiply both sides by two: B = 36 Now
we know the value of B and the value of H. Substitute this back into the second
equation and solve for T. T = H + 1/2B T = 9 + (1/2)36 T = 9 + 18 = 27 Step 4:
Plug all values of H, T, and B into the final equation. Total length of fish =
H + T + B Total length of fish = 9 +27 + 36 = 72.
I) Locus- the chromosomal site where a specific gene is located. A locus is a fixed position on a chromosome, like the position of a gene or a marker. Each chromosome carries ,many genes; human's estimated haploid (n) protein coding genes are about 20,000, on the 23 different chromosomes.
ii) Interference; the observed double crossover frequency differs from the expected double crossover frequency. Cross over interference is used to refer to the non-random placement of crossovers with respect to each other during meiosis. It results in widely spaced crossovers along chromosomes. Interference may exert its effect across whole chromosomes. As chromosomes in many eukaryotes are large, interference must be able to act over megabase lengths of DNA.
iii) Linkage- the tendency for genes located in close proximity on the same chromosome to be inherited together. Normally when two genes are close together on the same chromosome, they do not assort independently and are said to be linked. Whereas genes located on different chromosomes assort independently and have a recombination frequency of 50%, linked genes have a recombination frequency that is less than 50%.
iv) Recombination- the process by which a new pattern of alleles on a chromosome is generated. Genetic recombination is the production of offspring with combinations f traits that differ from those found in either parent. During meiosis in eukaryotes, genetic recombination involves the pairing of homologous chromosomes. This may be followed by information transfer between the chromosomes.
D since democracy takes decisions from most or all of the people and it tends to be the most fair method.
Answer:
Third-degree burns destroy the epidermis and dermis. They may go into the innermost layer of skin, the subcutaneous tissue. The burn site may look white or blackened and charred.
Explanation:
The treatment of third-degree burns may require the process of skin grafting or the use of synthetic skin. Severe burns covering large parts of the body may need more intensive treatments such as intravenous (IV) antibiotics to prevent infection or IV fluids to replace fluids lost when skin was burned.