Answer:
Testing Platismatia glauca could help scientists understand which pollutants have the largest effect on lichen populations. It also may help scientists understand the current pollutant levels in the atmosphere compared to the population of lichens on the trees. This information can help them more accurately predict population changes over time.
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Answer:
<u>independent variable:</u> size of soccer ball
<u>dependent variable</u>: period of time the balls stay in the air
<u>control variable</u>: parts of the body used to juggle the ball
Explanation:
The independent variable is the manipulatable variable supplied into an experiment. It is a variable that directly affects the dependent variable.
The independent variable is the outcome variable. It is the variable that is primarily measured from experiments whose value depends on the value of the independent variable.
The control variables are those that are kept constant throughout the course of experiments. In other words, they do not directly affect experimental outcomes.
Hence, in the illustration;
<u>independent variable</u>: size of soccer ball
<u>dependent variable</u>: period of time the balls stay in the air
<u>control variable</u>: parts of the body used to juggle the ball
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
