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Viktor [21]
2 years ago
11

The prosthetic group of hemoglobin and myoglobin is . The organic ring component of heme is . Under normal conditions, the centr

al atom of heme is . In , the central iron atom is displaced 0.4 Å out of the plane of the porphyrin ring system. The central atom has bonds: to nitrogen atoms in the porphyrin, one to a residue, and one to oxygen.
Biology
1 answer:
SVEN [57.7K]2 years ago
4 0

The question is incorrect. The correct question is as follows:

The prosthetic group of hemoglobin and myoglobin is _______?

The organic ring component of heme is _______?

Under normal conditions, the central atom of heme is ________?

In ________ the central iron atom is displaced 0.4 A out of the plane of the porphyrin ring system.

The central iron atom has _______ bonds: ________ to nitrogen atoms in the porphyrin, one to a _______ residue and one to oxygen.

Answer:

The hemoglobin is an important protein that transport oxygen in the body and contains the pigment that gives the red color to the red blood cells. The myoglobin protein is responsible for transport of oxygen in muscles.

The heme molecule acts as prosthetic group for both myoglobin and hemoglobin. The porphyrin ring is present in heme molecule. The iron molecule especially Fe2+ is present in heme molecule. The deoxyhemoglbin states occur when the central atom is displaced 0.4 Å. The iron central atom can form six bonds and forms four bonds with the prophyrin of nitrogen and one bond with histidine molecule. Histidine acts as a buffer fir the blood.

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MAVERICK [17]
Percent error is calculated by the expression:

%error = |actual value - observed value| / actual value x 100

We calculate the error of the values as follows:

<span>a. 23.487 cm
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b. 23.493 cm
</span>% error = |23.490  - 23.493| / 23.490 x 100 = 0.013%
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c. 23.516 cm
</span>% error = |23.490  - 23.516| / 23.490 x 100 = 0.11%<span>

d. 23.501 cm
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e. 23.477 cm
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1 year ago
12In an experiment, a petri dish with a colony of bacteria is exposed to cold temperatures and then warmed again.
klemol [59]
<span>Let the equation be : at^2 + bt + c = P,
where t = time (hrs),
P = population (1000's).
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When t = 3, P = 1.17.
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The equation is therefore,
P = 0.38t^2 - 2.45t + 5.1
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