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White raven [17]
2 years ago
4

Draw Lewis structures for the following molecules. Be sure to minimize formal charges. (Click in the "draw structure" button to

launch the drawing utility.) (a) ICl (b) PH3 draw structure ... draw structure ... (c) N2H4 (d) HClO3 draw structure ... draw structure ...

Chemistry
1 answer:
zmey [24]2 years ago
7 0

Answer :  The Lewis structures for the following molecules is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.

In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.

(a) The given molecule is, ICl

As we know that iodine and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in ICl = 7 + 7 = 14

According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.

(b) The given molecule is, PH_3

As we know that hydrogen has '1' valence electron and phosphorous has '5' valence electrons.

Therefore, the total number of valence electrons in PH_3 = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(c) The given molecule is, N_2H_4

As we know that hydrogen has '1' valence electron and nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in N_2H_4 = 2(5) + 4(1) = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(d) The given molecule is, HClO_3

As we know that hydrogen has '1' valence electron, oxygen has '6' valence electrons  and chlorine has '7' valence electrons.

Therefore, the total number of valence electrons in HClO_3 = 1 + 7 + 3(6) = 26

According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.

Hence, the Lewis structures for the following molecules is shown below.

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The answer to your question is below:

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