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umka2103 [35]
2 years ago
8

Given positive integer num_insects, write a while loop that prints that number doubled up to, but without exceeding 100. Follow

each number with a space. Sample output with input: 8 8 16 32 64
Computers and Technology
1 answer:
nasty-shy [4]2 years ago
5 0

Answer:

import java.util.Scanner;

public class CocaColaVendingTest {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter value for number of insects");

       int num_insects = in.nextInt();

       while (num_insects<=100){

           System.out.print(num_insects);

           num_insects*=2;

           System.out.print(" ");

       }

   }

}

Explanation:

In the code above written in Java.

The user is prompted to enter a positive value for the number of insects

This is stored in a variable num_insects.

Using a while loop with the condition while (num_insects<=100). The num_insects is printed out. Then it is doubled followed with a space.

It continues until the condition in the while loop is no longer true

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Given three dictionaries, associated with the variables, canadian_capitals, mexican_capitals, and us_capitals, that map province
Nookie1986 [14]

Answer:

The Python code to combine the three dictionaries are is given as follows:

  1. canadian_capital = {
  2.    cash: "SOME VALUES",
  3.    assets: "SOME VALUES"
  4. }
  5. mexican_capital = {
  6.    cash: "SOME VALUES",
  7.    assets: "SOME VALUES"
  8. }
  9. us_capital = {
  10.    cash: "SOME VALUES",
  11.    assets: "SOME VALUES"
  12. }
  13. nafta_capital = {
  14.    canadian: canadian_capital,
  15.    mexican : mexican_capital,
  16.    us: us_capital
  17. }

Explanation:

<u>Line 1 - 14 :</u>

Create three Python dictionaries and name them as <em>canadian_capitals, mexican_capital </em>and<em> us_capitals</em>. Please note a Python dictionaries should be enclosed in curly braces { }.  

We just define two samples of relevant keys (<em>cash </em>and <em>asset</em>) in each of the dictionaries. Python dictionary can map a key to a value.

Since we are not given any capital values from the question,  a dummy string "<em>SOME VALUES</em>" is tentatively set as the value for each of the keys.

In practice, we should replace those dummy strings with the real values of capital. The values can be a number, a string, a list and even a nested dictionary.

<u>Line 16 - 20 : </u>

Create one more Python dictionary and name it as <em>nafta_capital</em>.

Since our aim is to combine the three previous dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em>) and associate it with <em>nafta_capital</em>, we can define three different keys (<em>canadian, mexican </em>and <em>us</em>) in our dictionary nafta_capital.

As mentioned, a value associated with a key can be a nested dictionary. Hence, we just map <em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> as the value of the keys (<em>canadian, mexican </em>and<em> us</em>) in dictionary<em> nafta_capital,</em> respectively,

By doing so, we have managed to combine three target dictionaries (<em>canadian_capitals, mexican_capital </em>and <em>us_capitals</em> ) into a single dictionary, <em>nafta_capital</em>.

4 0
2 years ago
Our company is only interested in purchasing a software upgrade if it leads to faster connectivity and data sharing. The old sof
Igoryamba

Answer:

Calculate the average processing time of the new software

Explanation:

Since the average processing time of the old software is already known, the simplest test to see if the new software is faster than the old software will be to calculate the average processing time for the new software and compare it with the average processing time of the old software.

If the new software have an average processing time lower/smaller than that of the old software; we conclude that the new software is faster.

If the new software have an average processing time higher/larger than that of the old software; we conclude that the old software is faster.

6 0
2 years ago
In this problem we consider sending real-time voice from Host A to Host B over a packet-switched network (VoIP). Host A converts
Minchanka [31]

Answer:

<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>

Explanation:

Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:

time taken 1= \frac{Packet Size in Bits}{Bit Rate}

                 = (56 x 8) bits / 64 x 10³ bits/s

                 = 7 x 10⁻³s

time taken 1= 7 ms

The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:

time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s

                    = 1.12 x 10⁻⁴ s

time taken 2= 112 μs

The propagation delay is 18 ms.

To calculate the total time elapsed, we need to add up all the time taken at each individual stage.

<u />Time_{total}<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>

                 = 7 ms + 112 μs + 18 ms

                 = 0.025112 s

Time_{total} = 25.11 ms

5 0
2 years ago
Give a recursive (or non-recursive) algorithm to compute the product of two positive integers, m and n, using only addition and
LiRa [457]

Answer:

Multiply(m,n)

1. Initialize product=0.

2. for i=1 to n

3.      product = product +m.

4. Output product.

Explanation:

Here we take the variable "product" to store the result m×n. And in this algorithm we find m×n by adding m, n times.

6 0
2 years ago
Write a program that repeatedly reads in integers until a negative integer is read. The program keeps track of the largest integ
vfiekz [6]

Answer:

In Python:

num = int(input("Enter number: "))

maxn = num

while num >=0:

   if num>maxn:

       maxn = num

   num = int(input("Enter number: "))

print("Largest: "+str(maxn))

Explanation:

Get input from the user

num = int(input("Enter number: "))

Initialize the largest to the first input

maxn = num

This loop is repeated until a negative input is recorded

while num >=0:

If the current input is greater than the previous largest

   if num>maxn:

Set largest to the current input

       maxn = num

Get another input from the user

   num = int(input("Enter number: "))

Print the largest

print("Largest: "+str(maxn))

5 0
2 years ago
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