Answer:
C. The user will not be able to see the junction object records or the field values.
Explanation:
For the profile of the user to give access permission such as create and read to the job without granting access permission to the production facility object, the value of the field or records of the junction object will not be seen by the user. This is one of the necessary criteria or principle for the universal container with a junction object.
Answer:
1. Costs and frequency of change.
2. The most important ‘non-functional’ requirements. Different systems have different priorities for non-functional requirements.
3. The software lifetime and delivery schedule.
Explanation:
The process of requirement gathering is required in both generic and customized software.
• A document to define the development process is required in all type of software application.
• Updating is required in each type of software. For doing so, new version of each type of software is released.
• Maintenance is an important part of software development. It is required in each type of application development.
• Software has some minimum requirements to execute. So, platform dependability is considered in all software development.
Answer:
1.312 in
Explanation:
Data provided in the question:
Weight of the compressor, W = 227 pound
Number of legs = 4
Maximum pressure = 42 psi
Now,
Let F be the force taken by the legs
Therefore,
W = 4F
or
227 pound = 4F
or
F = 56.75 pounds
Also,
Force = Pressure × Area
or
56.75 pounds = 42 psi × πr² [ r is the diameter of one leg]
or
r² = 0.4301
or
r = 0.656
therefore,
diameter = 2r = 2 × 0.656
= 1.312 in
Answer: The electric field decreases because of the insertion of the Teflon.
Explanation:
If the charge on the capacitor is held fixed, the electric field as a consequence of this charge distribution (directed from the positive charged plate to the negative charged one remains unchanged.
However, as the Teflon is a dielectric material, even though doesn't allow the free movement of the electrons as an answer to an applied electric field, it allows that the electrons be displaced from the equilibrium position, leaving a local negative-charged zone close to the posiitive plate of the capacitor, and an equal but opposite charged layer close to the negative plate.
In this way, a internal electric field is created, that opposes to the external one due to the capacitor, which overall effect is diminishing the total electric field, reducing the voltage between the plates, and increasing the capacitance proportionally to the dielectric constant of the Teflon.
Answer:
1.505
Explanation:
cylindrical part of diameter d is loaded by an axial force P. This causes a stress of P/A, where A = πd2/4. If the load is known with an uncertainty of ±11 percent, the diameter is known within ±4 percent (tolerances), and the stress that causes failure (strength) is known within ±20 percent, determine the minimum design factor that will guarantee that the part will not fail.
stress is force per unit area
stress=P/A
A = πd^2/4.
uncertainty of axial force P= +/-.11
s=+/-.20, strength
d=+/-.04 diameter
fail load/max allowed
minimum design=fail load/max allowed
minimum design =s/(P/A)
sA/P
A=(
.96d^2)/4, so Amin=
(because the diameter at minimum is (1-0.04=0.96)
minimum design=Pmax/(sminxAmin)
1.11/(.80*.96^2)=
1.505