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katrin [286]
1 year ago
13

Lucy Baker is analyzing demographic characteristics of two television programs: COPS (population 1) and 60 Minutes (population 2

). Previous studies indicate no difference in the ages of the two audiences. (The mean age of each audience is the same.) Lucy plans to test this hypothesis using a random sample of 100 from each audience.
A) Her alternate hypothesis is __________.
Mathematics
1 answer:
drek231 [11]1 year ago
7 0

Answer and Explanation:

Her alternative hypothesis is that there is some difference between the means of the ages of the audiences of the two television programs. That is, the mean ages of the two audiences are not the same.

If the mean of the ages of the audiences of television programme 1 (COPS) is xbar₁

And the mean of the ages of the audiences of the television programme 2 (60 minutes) is xbar₂

Her alternative hypothesis can be represented mathematically as

xbar₁ - xbar₂ ≠ 0

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In the diagram, P1P2 and Q1Q2 are the perpendicular bisectors of line AB and BC , respectively. A1A2 and B1B2 are the angle bise
Aliun [14]
I hope I can show the image, but I hope this may help you, the answer is:

The center of the inscribed circle of ΔABC is <u>point S</u> , and the center of the circumscribed circle of ΔABC is <u>point P.</u>
4 0
2 years ago
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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If
Molodets [167]

Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

p=1-e^{-mt}

You know that:

The number of  customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

m=6

As the problem asked for the probability that  a costumber will be on hold less than 30 minutes, we know that:

t=0.5

Substitute the values above into the formula.

Then, you obtain:

p=1-e^{-(6)(0.5)}=0.95 or 95%

7 0
1 year ago
Write the perimeter of the floor plan shown as an algebraic expression in x.
Nimfa-mama [501]
The perimeter is the sum of the enclosing side.

From the figure, the perimeter is
P = 11 + (x-2) + (11-3) + [(x-2) - (x-11)] + (x-11)
   =  11 + x - 2 + 8 + 9 + x - 11
   = 2x + 15

Answer:  2x + 15

5 0
2 years ago
A university warehouse has received a shipment of 25 printers, of which 10 are laser printers and 15 are inkjet models. If 6 of
Tanya [424]

Answer:

The probability is 0.31

Step-by-step explanation:

To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.

In this case, the event of interest is  choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is \binom{25}{6}, where \binom{n}{k} = \frac{n!}{(n-k)!k!}. We have that \binom{25}{6} = 177100

Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in \binom{10}{3}\cdot \binom{15}{3} = 54600

So the probability of having 3 laser printers and 3 inkjets is given by

\frac{54600}{177100} = \frac{78}{253} = 0.31

4 0
2 years ago
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