Solving this problem needs the distance formula of point to a line.
The formula is:
distance = | a x + b y + c | / √ (a^2 + b^2)
So we are given the equation: y = 2 x + 4
Rewriting this would be: y – 2 x – 4 = 0 -> a = -2, b = 1, c = -4
We are also given the points:
(-4, 11) = (x, y)
Plugging it in the distance formula at points (x, y):
distance = | -2 * -4 + 1 * 11 + -4 | / √ [(- 2)^2 + (1)^2]
= 15 / √ (5)
= 6.7
So the tree is approximately 6.7 feet away from the zip line.
The correct answer for the exercise shown above, is the first option (Option A), which is:
A. <span>(1+1/18)^18
The explanation is shown below:
1- You have that the number e is an irrational number, therefore, its value is aproximated:
e=2.7182
2- You have the following expressions:
</span>(1+1/18)^18=2.6464
<span>(1+1/17)^17=2.6424
</span><span>(1+1/16)^16=2.6379
</span><span>(1+1/15)^15=2.6328
Therefore the value of the expression that is closest to e is the Option A.</span>
Answer:
i would guese c
Step-by-step explanation:
The average of the set of numbers is the quotient when the sum of the numbers is divided by the number of items. Given that Markus' fifth score x, the average is x+5. The equation for solving the fifth score and the arithmetic mean is,
(85 + 92 + 82 + 94 + x) / 5 = x + 5
Further simplifying gives,
(353 + x) / 5 = x + 5
Calculating for the value of x gives x = 82.
<h2><u>
PLEASE MARK BRAINLIEST!</u></h2>
Answer:
The answer is... 20, 90, 8
Step-by-step explanation:
What is the range of Charles’s scores?
<h3>20</h3>
What is the median of Charles’s scores?
<h3>90</h3>
What is the IQR of Charles’s scores?
<h3>8</h3>
If you move the graph to its correct spot, your answers will be clear.
I hope this helps!
- sincerelynini
