Markus scored 85, 92, 82, and 94 on the first four tests of the semester. his teacher has not yet told him his score on his fift
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Alright, so we are dealing with permutations. Permutations are the number of combinations in a specific order possible for the set.
There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:
number of elements in the subset
number of elements in the set
permutations of the set
There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.
Here's the math:
There are 24 permutations. I can prove this by showing you the model:
ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.
Hope this helps!
Answer: 24 passwords are possible
There's 4 letters, each one can be paired with 3 other letters, but those letters could be in different orders. To figure out how many variations of each combination there are (aka the number of permutations) use this formula:
There are only 3 elements in the subset because there is 1 that will not be repeated in each set, and there are 4 elements in the set.
Here's the math:
There are 24 permutations. I can prove this by showing you the model:
ABCD, ABDC, ACBD, ACDB, ADBC, ADCB are the 6 arrangements possible of the set starting with the letter A. Because there are 4 letters, the total amount of permutations without repeated letters is 4 (letters) times 6 (possible arrangements), which equals 24.
Hope this helps!
Answer: 24 passwords are possible