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2 years ago

7

Given the functions k(x) = 2x2 − 8 and p(x) = x − 4, find (k ∘ p)(x).

2 answers:

sweet-ann [11.9K]2 years ago

7 0

$(k_ {0} p) (x) = 2x^2 -16x + 24$

<em><u>Solution:</u></em>

<em><u>Given functions are:</u></em>

$k(x) = 2x^2 - 8\\\\p(x) = x-4$

To Find: $(k_ {0} p) (x)$

By definition of compound functions,

$(k_ {0} p) (x) = k (p (x))$

Substitute p(x) value in x place in k(x)

$(k_ {0} p) (x) = 2(x-4)^2-8\\\\Expand\\\\(k_ {0} p) (x) =2(x^2 -8x +16) - 8\\\\(k_ {0} p) (x) = 2x^2 -16x + 32-8\\\\Simplify\\\\(k_ {0} p) (x) = 2x^2 -16x + 24$

Thus the required is found

geniusboy [140]2 years ago

3 0

Answer:

The answer is A. (k o p) (x)=2x^2-16x+24

Step-by-step explanation:

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